Answer:
The probability that the mean delivery time from the sample of 25 orders xˉ is farther than 2 minutes from the population mean cannot be calculated.
Step-by-step explanation:
As given in the question statement, the distribution of delivery times is strongly skewed to the right. The population distribution is skewed to right. Too much skewed distribution can cause the statistical model to work ineffectively and affects its performance. The probability can also not be calculated because the sample size is too small. Small sample size affects the results and makes them less reliable because it results in a higher variability and likelihood of skewing the results.
1 foot = 12 inches
12 1/2 or 12.5 inches
18 and 3/4 or 18.75 X 12= 225
The ratio is 12.5:225 or to simplify 1:18.
Answer:
132 days to 125.4 days percent of change
Step-by-step explanation:
p= N-O/O x 100% where p is the percent change, is the New value and O is
the Old value. We are given the Old value (132) and the New value (125.4) which we can substitute into the formula to calculate the percent change:
p= 125.4-132/132 x 100%
p= -6.6/132 x 100%
p= (-660/132%)
p= -5%
Answer:
The lines would be equal, meaning the slope of the red line is also -3.
Step-by-step explanation:
SIMPLE:
Parallel lines have the same slope.
When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2
<h3>Data obtained from the question</h3>
- [(x^2)^3 × 5x] / [6x^2 × 15x^3]
- Simplification =?
<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>
[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Recall
(M^a)^b = M^ab
Thus,
(x^2)^3 = x^6
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]
Recall
M^a × M^b = M^(a+b)
Thus,
x^6 × 5x = 5x^(6 + 1) = 5x^7
6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5
- [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5
Recall
M^a ÷ M^b = M^(a - b)
Thus,
5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2
Therefore,
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2
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