Answer:
Data set B would have flatter distribution with more data in each tail.
Step-by-step explanation:
We are given the following in the question:
Data set A has a smaller standard deviation than data set B.
Standard Deviation:
- It is a measure of dispersion of data.
- It tells us about how much the data deviates around the mean.
- It tells us about the overall deviation of the data from the mean.
- The standard deviation is small when the data are all close to the mean showing less variation.
- The standard deviation is larger when the data values are farther away from the mean, showing more variation.
Since data A has less standard deviation than data B, then data B has a flatter graphical representation as more of the data are present on the tails.
Answer:
When we have a function f(x), the average rate of change in the interval (a, b) is:
In this case, we have the function:
f(x) = (x + 3)^2 - 2
(but we do not have the interval, and I couldn't find the complete question online)
So if for example, we have the interval (2, 4)
The average rate of change will be:
If instead, we want the rate of change in a differential dx around the value x, we need to differentiate the function (this is way more complex, so I will define some rules first).
Such that the rate of change, in this case, will be:
f'(x) = df/dx
For a function like:
g(x) = x^n + c
g'(x) = n*x^(n - 1)
And for:
h(x) = k( g(x))
h'(x) = k'(g(x))*g'(x)
So here we can write our function as:
f(x) = k(g(x)) = (x + 3)^2 - 2
where:
g(x) = x + 3
k(x) = x^2 - 2
Then:
f'(x) = 2*(x + 3)*1 = 2*x + 6
That is the rate of change as a function of x (but is not an "average" rate of change)
A Cartesian coordinate system is a coordinate system that specifies each point uniquely in a plane by a pair of numerical coordinates, which are the signed distances to the point from two fixed perpendicular directed lines, measured in the same unit of length.
A' 1,-1
b' 3,-1
c' 3,-4
d' 1,-4
