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Temka [501]
3 years ago
13

20. Isosceles trapezoid LMNO has vertices L(-4,-3), M(-4,0), N(-2, 1),and O(-2,-4). If the figure is

Mathematics
1 answer:
kvv77 [185]3 years ago
6 0

Answer:

L’M’ = 4.5 units

Step-by-step explanation:

We start by getting the dilated coordinates

we specifically work with the points LM

The dilated points can be obtained by multiplying the individual coordinates by 1.5

for L (1.5 * -4 and 1.5 * -3) = L’ (-6, -4.5)

M (-4,0) and ; (1.5 * -4 and 0 * 1.5) = M’ (-6,0)

Now, we can use the distance formula

D = √(y2-y1)^2 + (x2-x1)^2

D = √(0+ 4.5)^2 + (-6+6)^2

D = √(4.5)^2

D = 4.5 units

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42 pieces of candy divided between three people. You put candy in three boxes. How many pieces of candy are there in per box?
Salsk061 [2.6K]

Answer:

There are 14 pieces of candy in each box.

Step-by-step explanation:

42 divided by 3 equals 14.

<u><em>Could I please have Brainliest.</em></u>

5 0
3 years ago
Solve for n.<br> 2n - 3<br> 5<br> =<br> = 5<br> Enter your answer in the box.<br> n =
Zina [86]

Answer:

2n - 35 = 5 \\ 2n = 5 + 35 \\ 2n = 40 \\ n = 40 \div 2 \\ n = 20

4 0
3 years ago
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A square with side x is changing with time where x(t)=3t+1. What is rate of change of the area of the square when t=2 seconds.
GuDViN [60]

Answer:

Rate of change of the area of the square is 42 units at t = 2.

Step-by-step explanation:

We note that the area of the square is given by: A(x) = x^2 but we aim to find \frac{dA}{dt}. But we can use the chain rule to pull out that dA/dt. Doing so gives us:

\frac{dA}{dt} = \frac{dA}{dx} \times \frac{dx}{dt}.

Now, \frac{dA}{dx} = 2x (by the power rule and \frac{dx}{dt} = 3.

But since we have "x" and not "t", we want to find what x is when t = 2. Substituting t = 2 gives us x(2) = 3(2) + 1 = 7.

So, finally, we see that:

\frac{dA}{dt} = 2(7) \times 3 = 14 \times 3 = 42.

7 0
3 years ago
ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)
Delicious77 [7]
remember
ln(x)=log_e(x)
and
log_x(a)-log_x(b)= log_x( \frac{a}{b} )
and
log_a(b)=c means a^c=b
and
blog(a)=log(a^b)



so

ln(y+1)-ln(y)=1+3ln(x)
ln( \frac{y+1}{y} )=1+ln(x^3)

minus ln(x^3) from both sides

ln( \frac{y+1}{y}-ln(x^3) )=1
ln( \frac{y+1}{yx^3})=1
log_e( \frac{y+1}{yx^3})=1

translate

e^1=\frac{y+1}{yx^3}
e=\frac{y+1}{yx^3}

times both sides by yx^3

eyx^3=y+1

minus y from both sides

eyx^3-y=1
y(ex^3-1)=1

divide both sides by (ex³-1)

y= \frac{1}{ex^3-1}
6 0
3 years ago
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Question with last attempt is displayed for your review only
Alika [10]

Answer:

43.13 = 5.25h + 9

Step-by-step explanation:

Let's solve this by making an equation.

$9 for the helmet, and $5.25 per hour.

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C = 5.25h + 9

Now, substitute in what we learned from the problem.

43.13 = 5.25h + 9

This is an equation you can use to solve for the hours.

3 0
3 years ago
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