Express tan in terms of sin and cos
= sin ax cos bx / sin bx
Now I'm stuck! sorry
For what its worth Ive drawn the graph and the answer is a/b
Answer:
10 hours lifeguarding, 6 hours tutoring
Step-by-step explanation:
As you know how long he worked and how much he earned, it's worth seeing how many hours it would have been had he worked just tutoring or just lifeguarding.
$242 / 11 = 22 hours if it was just lifeguarding
$242 / 22 = 11 hours (as it's exactly double the wage) if it was just tutoring
We now know that he worked some combination of both
Calculating his average wage can help work out which he worked more of:
$242 / 16 = 15.125
That means Parker's average hourly wage was 15.125 which is closer to 11 than 22 (16.50 would mean an exactly even split between the two) so he did more hours lifeguarding than tutoring so more than 8 hours.
What I then do is consider the variations that could work:
9 (lifeguarding) and 7 (tutoring) = 99 + 154 = 243
So we're almost exactly there straight away, but not quite so...
10 and 6 = 110 + 132 = 242
There you have it.
Answer:
We verified that ![a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]](https://tex.z-dn.net/?f=a%5E3%2Bb%5E3%2Bc%5E3-3abc%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%5B%28a-b%29%5E2%2B%28b-c%29%5E2%2B%28c-a%29%5E2%5D)
Hence proved
Step-by-step explanation:
Given equation is
We have to prove that
That is to prove that LHS=RHS
Now taking RHS
![\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]](https://tex.z-dn.net/?f=%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%5B%28a-b%29%5E2%2B%28b-c%29%5E2%2B%28c-a%29%5E2%5D)
![=\frac{a+b+c}{2}[a^2-2ab+b^2+b^2-2bc+c^2+c^2-2ac+a^2]](https://tex.z-dn.net/?f=%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%5Ba%5E2-2ab%2Bb%5E2%2Bb%5E2-2bc%2Bc%5E2%2Bc%5E2-2ac%2Ba%5E2%5D)
(using 
)
![=\frac{a+b+c}{2}[2a^2-2ab+2b^2-2bc+2c^2-2ac]](https://tex.z-dn.net/?f=%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%5B2a%5E2-2ab%2B2b%5E2-2bc%2B2c%5E2-2ac%5D)
(adding the like terms)
![=\frac{a+b+c}{2}[2a^2+2b^2+2c^2-2ab-2bc-2ac]](https://tex.z-dn.net/?f=%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%5B2a%5E2%2B2b%5E2%2B2c%5E2-2ab-2bc-2ac%5D)
![=\frac{a+b+c}{2}\times 2[a^2+b^2+c^2-ab-bc-ac]](https://tex.z-dn.net/?f=%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%5Ctimes%202%5Ba%5E2%2Bb%5E2%2Bc%5E2-ab-bc-ac%5D)
![=a+b+c[a^2+b^2+c^2-ab-bc-ac]](https://tex.z-dn.net/?f=%3Da%2Bb%2Bc%5Ba%5E2%2Bb%5E2%2Bc%5E2-ab-bc-ac%5D)
Now multiply the each term to another each term in the factor
![=a^3+ab^2+ac^2-a^2b-abc-a^2c+ba62+b^3+bc^2-ab^2-b^2c-abc+ca^2+cb^2+c^3-abc-bc^2-ac^2]](https://tex.z-dn.net/?f=%3Da%5E3%2Bab%5E2%2Bac%5E2-a%5E2b-abc-a%5E2c%2Bba62%2Bb%5E3%2Bbc%5E2-ab%5E2-b%5E2c-abc%2Bca%5E2%2Bcb%5E2%2Bc%5E3-abc-bc%5E2-ac%5E2%5D)
(adding the like terms and other terms getting cancelled)
=LHS
Therefore LHS=RHS
Therefore
Hence proved.
The first thing we need to find out is your strategy so we are using algebra right? the first thing your gonna do is find the formula?
