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Digiron [165]
3 years ago
15

Describe the somatic division of the peripheral nervous system, include specific functions and responsibilities.

Advanced Placement (AP)
1 answer:
lawyer [7]3 years ago
4 0

Answer:

The somatic nervous system is the part of the peripheral nervous system that is responsible for carrying motor and sensory information both to and from the central nervous system (CNS).

Explanation:

The primary function of the somatic nervous system is to connect the central nervous system to the body's muscles to control voluntary movements and reflex arcs. Information taken in by sensory systems is transmitted to the central nervous system. The CNS then sends signals via the nerve networks of the somatic system to the muscles and organs.

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Why is it important for people onstage and offstage in the theater to use the same vocabulary
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Explanation:

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What can a state do if they disagree with a supreme court ruling?
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Answer:

Explanation:

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3 years ago
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4 years ago
Match the correct efta and pci standards ?
Snezhnost [94]
Yes!!!!!! That is correct answer
7 0
3 years ago
I can’t figure this problem out
Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

\int\limits^4_1 {(3f(x)+2)} \, dx

So lets break this up into two different integrals that represent the same area.

\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

\int\limits^4_1 {f(x)} \, dx

But since we have these values we can say that:

-3 - 2 = -5

Which means that \int\limits^4_1 {f(x)} \, dx = -5

So now we can evaluate \int\limits^4_1 {(3f(x)+2)} \, dx

Lets first break up our integrand into two integrals

\int\limits^4_1 {(3f(x)+2)} \, dx = 3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx

Now we can evaluate this:

We know that \int\limits^4_1 {f(x)} \, dx = -5

So:

3(-5)+2[x] where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

5 0
3 years ago
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