Answer: -1
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given the functions
F(x) = 6-x²
G(x) = x²+4x-12
A) we are to find F(x)+g(x)
F(x)+G(x) = 6-x²+x²+4x-12
F(x)+G(x) = 6+0+4x-12
F(x)+G(x) = 4x+6-12
F(x)+G(x) = 4x-6
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER
F(x)-g(x) = 6-x²-(x²+4x-12)
F(x)-g(x) = 6-x²-x²-4x+12
F(x)-g(x) = 6-2x²+4x+12
F(x)-g(x) = -2x²+4x+6
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER
3) F(x)/G(x)
= 6-x²/x²+4x-12
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER
1). X= 1
2). x = 4
3). x = 2
4). x = 3
Try going with these ↑
Answer:
x = 2
Step-by-step explanation:
7x−5=2x+5
step 1 add 5 to each side
-5 + 5 = cancels out
5 + 5 = 10
we now have 7x = 2x + 10
step 2 subtract 2x from each side
2x - 2x cancels out
7x - 2x = 5x
we now have 10 = 5x
step 3 divide each side by 5
5x / 5 = x
10 / 5 = 2
we' re left with x = 2
Answer:
g(20) = 70
Step-by-step explanation:
g(x) = 15 . 2 + 2x
g(20) = 15 . 2 + 2(20)
g(20) = 30 + 40
g(20) = 70
