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kozerog [31]
3 years ago
11

Draw a vector representing the course of a ship that goes 75 miles on a

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

The answer is below

Step-by-step explanation:

We have a vector with a magnitude of 75 miles and a direction of 300 °.

To draw it, the first thing is to make a Cartesian plane, the first thing is to know in which quadrant it would be, 300 ° is in the fourth quadrant (270 ° - 360 °), that is, it would be 30 ° (300 ° - 270 °) with respect to to the y axis negative.

Knowing this angle, we calculate the value of x and y, knowing that the magnitude of the vector is 75 miles, that is, this value would be the hypotenuse.

The value on the x-axis can be calculated using the sine of the angle, like this:

sin 30 ° = x / 75

x = sin 30 ° * 75

x = 37.5

Now to calculate the value on the y-axis it would be by means of Pythagoras and it would be:

y ^ 2 = 75 ^ 2 - 37.5 ^ 2

y ^ 2 = 4218.75

y = 64.95, -64.95 because it must be located in the fourth quadrant

Which means that to draw the vector that we are asked to do, we must draw a point from origin (0,0) to (37.5, -64.95).

Then I leave a sketch of what it would be:

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3 years ago
Find all the missing elements:
pshichka [43]

Answer:

C = 21.78 and a= 8.88

Step-by-step explanation:

Here, sides b=7 and c=3

Also, Angle B=60

Angle B is between side c and a

It can be solve by cosine rule and sin rule

sin rule says,

\frac{a}{sinA}  = \frac{b}{sinB}  = \frac{c}{sinC} \\  \frac{a}{sinA}  = \frac{7}{sin60}  = \frac{3}{sinC}  \\ \frac{7}{sin60}  = \frac{3}{sinC}  \\ sinC = \frac{3}{7} \: sin60 = 0.3711537445 \\  \\ C =  21.78

cosine rule says,

{a}^{2}  =   {b}^{2}  +  {c}^{2}  + 2bc  \: cos(B) \\ {a}^{2}  =   {7}^{2}  +  {3}^{2}  + 2(7)(3)  \: cos(60) \\ {a}^{2}  =   49 +  9 + \:21 = 79 \\ a = 8.88

7 0
3 years ago
Write in slope intercept form an equation of the line that passes through (-2,5),(-1,1)
Juliette [100K]

Answer:

y=-4x-3

Step-by-step explanation:

Hi there!

We are given the following two points: (-2,5) and (-1,1)

We want to write the equation of the line that passes through these two lines in slope-intercept form

Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept

First, let's find the slope

The formula for the slope (m) calculated from 2 points is \frac{y_2-y_1}{x_2-x_1}, where (x_1, y_1) and (x_2, y_2) are points

We have everything we need to calculate the slope, but let's label the value of the points to avoid any confusion

x_1=-2\\y_1=5\\x_2=-1\\y_2=1

Now substitute into the formula

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{1-5}{-1--2}
Simplify

m=\frac{1-5}{-1+2}

Subtract

m=\frac{-4}{1}

Divide

m=-4

Now substitute -4 as m into the equation:

y=-4x+b

Now we need to find b

As the equation passes through both (-2, 5) and (-1, 1), we can use either point to help solve for b.

Taking (-2,5) for example:

Substitute -2 as x and 5 as y:

5=-4(-2)+b

Multiply

5=8+b

Subtract 8 from both sides

-3=b

Substitute -3 as b.

y=-4x-3

Hope this helps!

See more on this topic here: brainly.com/question/27304092

4 0
2 years ago
What is the equation in slope-intercept form for the line that passes through the points (−2, −1) and (1, 5)?
12345 [234]

Answer:

y=2x+3

Step-by-step explanation:

we know the slope is 2

now we are going to find b

-1=2(-2)+b

-1=-4+b

-1+4=3

3=b

7 0
3 years ago
What is 60 percent of 20
ikadub [295]
The 60 percent of 20 is 12
8 0
3 years ago
Read 2 more answers
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