Draw a vector representing the course of a ship that goes 75 miles on a
1 answer:
Answer:
The answer is below
Step-by-step explanation:
We have a vector with a magnitude of 75 miles and a direction of 300 °.
To draw it, the first thing is to make a Cartesian plane, the first thing is to know in which quadrant it would be, 300 ° is in the fourth quadrant (270 ° - 360 °), that is, it would be 30 ° (300 ° - 270 °) with respect to to the y axis negative.
Knowing this angle, we calculate the value of x and y, knowing that the magnitude of the vector is 75 miles, that is, this value would be the hypotenuse.
The value on the x-axis can be calculated using the sine of the angle, like this:
sin 30 ° = x / 75
x = sin 30 ° * 75
x = 37.5
Now to calculate the value on the y-axis it would be by means of Pythagoras and it would be:
y ^ 2 = 75 ^ 2 - 37.5 ^ 2
y ^ 2 = 4218.75
y = 64.95, -64.95 because it must be located in the fourth quadrant
Which means that to draw the vector that we are asked to do, we must draw a point from origin (0,0) to (37.5, -64.95).
Then I leave a sketch of what it would be:
You might be interested in
Answer:
Step-by-step explanation:
See attachment for complete question.
From the attachment:
Dilation:
Required
Determine R'
First, subtract the coordinates of P from R. This means that R is measured from P.
Next, apply dilation factor 0.5
Lastly, measure R' from the origin by adding the coordinates of P to R'
