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3 years ago

The spinner below is spun then the a month of the year is randomly selected. Find each probability

Mathematics

2 answers:

bulgar [2K]3 years ago

7 0

Answer:

Step-by-step explanation:

P (blue) fraction = 2/8 decimal=.25 percent=25%

P(purple) fraction=0/8 decimal=0 percent =0%

P(not green) fraction=5/8 decimal=.625 percent= 62.5%

P(not brown) fraction=8/8 decimal=1 percent =100%

2)Refer to the table on air travel selected airports. Suppose a flight that arrived at El Centro is selected at random. What is the probability that the flight did not arrive on time? write your answer as a fraction, decimal and percent.

80% on time so 20% are not on time

20/100 ÷ 20 =1/5

20%, .2, 1/5

3)The spinner has 8 sectors labeled with letters. Each sector of the spinner below is the same size, as shown.

If the arrow is spun 400 times , how many times would it be expected to land on a sector labeled B?

$\frac{B}{Total} \\\frac{3}{8} =\frac{x}{400\\}$

A)50 C)150

B)100 D)250

PLEASE MARK ME AS BRAINLIEST

Kryger [21]3 years ago

6 0

Answer:

I think the answer is 0.3

Step-by-step explanation:

Sorry if am wrong.

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PLZZ HELP I NEED ANSWER RNNNNNNB

poizon [28]

Answer:

Surface Area = 82.8 square meters

Volume = 37.96 cubic meters

Surface area:

6 × 2 = 12

9 × 2 = 18

8.8 × 6 = 52.8

12 + 18 + 52.8 = 82.8

Volume:

6 × 2 × 9.49 = 113.88

113.88 ÷ 37.96

5 0

4 years ago

A fish swam 75 feet to the bottom of the river. The fish then swam up 35 feet towards the surface of the river and stopped. How

telo118 [61]

Answer: 40

Step-by-step explanation:

75-35

5 0

3 years ago

Assume that foot lengths of women are normally distributed with a mean of 9.6 in and a standard deviation of 0.5 in.a. Find the

Makovka662 [10]

Answer:

a) 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b) 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c) 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 9.6, \sigma = 0.5$ .

a. Find the probability that a randomly selected woman has a foot length less than 10.0 in

This probability is the pvalue of Z when $X = 10$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10 - 9.6}{0.5}$

$Z = 0.8$

$Z = 0.8$ has a pvalue of 0.7881.

So there is a 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b. Find the probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

This is the pvalue of Z when X = 10 subtracted by the pvalue of Z when X = 8.

When X = 10, Z has a pvalue of 0.7881.

For X = 8:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{8 - 9.6}{0.5}$

$Z = -3.2$

$Z = -3.2$ has a pvalue of 0.0007.

So there is a 0.7881 - 0.0007 = 0.7874 = 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c. Find the probability that 25 women have foot lengths with a mean greater than 9.8 in.

Now we have $n = 25, s = \frac{0.5}{\sqrt{25}} = 0.1$ .

This probability is 1 subtracted by the pvalue of Z when $X = 9.8$ . So:

$Z = \frac{X - \mu}{s}$

$Z = \frac{9.8 - 9.6}{0.1}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772.

There is a 1-0.9772 = 0.0228 = 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

5 0

3 years ago

Find the product. 2 1/3 . 2 2/3 ? please show your work ty . A) 6 2/9 B) 5 C ) 1 2/3 D) 4 2/9

koban [17]

The answer is 6.2(A) Turn the mixed numbers into improper fractions b multiplying the whole number by the denominator. Do this for both fractions then multiply normally.

6 0

3 years ago

My daughter needs help with homework.

meriva

Just find the a common denominator between the two fractions and then add across

For example on the first one i'm going to turn each fraction into an improper fraction by multiplying the whole number by the denominator then adding that number to the numerator

2 1/8 = 17/8
4 2/3 = 14/3

Then multiply the denominators together to get 24 - this is the common denominator (24)

Figuring out the numerator is more complex - figure out what number needs to be multiplied to the original denominator that makes it 24 - then multiply that to the numerator. Add the two products and the answer should be 163/24.

This could be dead wrong because the number next to the fraction could be multiplying in - in that case the answer is 35/12 and has a completely different set of steps.

6 0

3 years ago