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larisa [96]
3 years ago
11

Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne

l syndrome (CTS). An article reported on a test that involved sensing a tiny gap in an otherwise smooth surface by probing with a finger; this functionally resembles many work-related tactile activities, such as detecting scratches or surface defects. When finger probing was not allowed, the sample average gap detection threshold for m = 8 normal subjects was 1.71 mm, and the sample standard deviation was .53; for n = 10 CTS subjects, the sample mean and sample standard deviation were 2.53 and .87, respectively.
Required:
a. Does this data suggest that the true average gap detection threshold for CTS subjects exceeds that for normal subjects?
b. State and test the relevant hypotheses using a significance level of 0.01.
Mathematics
1 answer:
hammer [34]3 years ago
4 0

Answer:

Hence, data does not suggest the true average gap detection threshold for CTS subjects exceeds that for normal subjects.

Step-by-step explanation:

H0 : μ1 = μ2

H1 : μ1 < μ2

Given :

m = 8 ; x1 = 1.71 ; s1 = 0.53

n = 10 ; x2 = 2.53 ; s2 = 0.87

The test statistic :

(x1 - x2) / √(s1²/m + s2²/n)

(1.71 - 2.53) / √(0.53²/8 + 0.87²/10)

-0.82 / √0.1108025

Test statistic = - 0.82 / 0.3328700

Test statistic = - 2.463

The degree of freedom using the conservative approach :

Smaller of (10 - 1) or (8 - 1)

df = 7

TCritical value(0.01, 7) = 2.998

Decision region :

Reject H0 if |Test statistic| > |critical value|

Since, 2.463 < 2.998 ; WE fail to reject H0 ; Hence result is not significant at α = 0.01

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JulsSmile [24]

Answer:

13 units

Step-by-step explanation:

(x₁,y₁) = (-5 , 3)   & (x₂ , y₂) = (7 ,8)

Distance = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}} \\

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7 0
3 years ago
Janice needs 3 gallons of lemonade for a party. She has 4 quarts, 6 pints, and 4 cups of lemonade already made. How much more le
Allisa [31]
4 quarts is 1 gallon
6 pints is 0.75 gallons
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so she would need 1 more gallon of lemonade
7 0
3 years ago
By drying tea leaves you can get 4.2% of its weight as tea. What weight of fresh tea leaves do you need to get 46.2 lb of tea? P
ratelena [41]

Answer:

Amount of tea leaves required = 1100 lb

Step-by-step explanation:

Given that:-

Tea leaves yields 4.2 % of the tea upon drying.

It means that if 100 lb of the tea leaves are taken, it will yield 4.2 lb of the tea.

To calculate:-

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Let the amount of tea leaves = x lb

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Thus,

\frac{4.2}{100}\times x=46.2

4.2x=4620

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6 0
3 years ago
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Answer:

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Question 7 of 10
Vsevolod [243]

Answer:

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6 0
3 years ago
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