Given two similar right triangles MIT and MSR such that side MR is an extension of side MT, side MS is an extension of side MI and the side IT is parallel to side SR.
Also, give that <span>If MS = 20 m, MT = 9 m, and RM = 12 m. To find the value of IM, we recall that the ratio of any two sides of a similar figure is equal to the ratio of the corresponding sides of the other triangle.
i.e. IM / MT = MS / RM
</span> IM / 9 = 20 / 12
IM = (9 x 20) / 12 = 15
Therefore, the measure of side IM is 15 m.
All exterior angles of a regular polygon would equal 360 degrees. SO... based on that, one exterior angle would have to multiplied by whatever sum (whole number) to equal 360 degrees to find the number of sides. Here you divide 360 by one of the exterior angles, if it does not equal a whole number then it would be inaccurate.
In this case only 54 degrees would not fit into one of the exterior angles.
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-x^5 - x^2+ 9
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