Answer:
The height would be 9.1923 ft
Answer:c+t<_27
Step-by-step explanation:
Use the points H(−4, 1) and K(4, 1).
(a) From two points , we will get a vertical line when 'x' values are same and horizontal line segment when 'y' values are same
Here in H(−4, 1) and K(4, 1) , the y values are same so the segment HK is a horizontal . The length is the difference between x values ( 4 -(-4)) = 8
Segment HK is a Horizontal segment that is
8 units long.
(b) Describe the image of segment HK under the transformation
(x, y) -----> (−y, x)
H(−4, 1) -----> (-1, -4)
and K(4, 1) ---> (-1, 4)
'x' values are same so line HK is Vertical. The length is the difference between y values ( 4 -(-4)) = 8
The image of segment HK is a Vertical segment that is
8 units long.
(c) escribe the image of segment HK under the transformation
(x, y) ----> (2x, y)
H(−4, 1) -----> (-8, 1)
and K(4, 1) ---> (8, 1)
'y' values are same so line HK is Horizontal. The length is the difference between y values ( 8 -(-8)) = 16
The image of segment HK is a Horizontal segment that is
16 units long.
Answer:
point ( 1 , 1 )
Step-by-step explanation:
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hope this help you !! :)))</h3>
Answer:
No. Operations manager cannot conclude that his mail-order business is achieving its goal.
Step-by-step explanation:
We make hypothesis test about the manager's assuption:
Null hypothesis, : Average number of days to fill customers' orders is six or less
Alternate Hypothesis: : Average number of days to fill customers' orders is more than six.
According to the null hypothesis we assume number of days to fill customers' orders follows a normal distribution with mean 6 and standard deviation 1.5. We would test if the sample mean is in the critical field or not in the given significance level.
One tailed critical value for the significance level 0.025 is 1.96. We'll compare this value with the z-score of the sample mean 6.65, which is calculated as:
z= ≈ 2.74 where
- 6,65 is the sample mean
- 6 is the null hypothesis
- 1.5 is the standard deviation
- 40 is the sample size
Since 2.74>1.96, we can conclude that sample mean is in the critical region, we reject the null hypothesis.
Therefore operations manager can conclude that average number of days to fill customers' orders is more than 6 days.