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Zielflug [23.3K]
3 years ago
14

Is this thesis OK for my schizophrenia essay? Schizophrenia is a severe mental illness that deeply affects the patient's daily l

ife
Thanks -MC
Mathematics
1 answer:
sattari [20]3 years ago
3 0
I don't know how many paragraphs your professor needs you to develop, but if your essay consists on just 3 paragraphs (introduction, body and conclusion) your thesis is OK.
Now, if your essay needs to have, lets say 4 or 5 paragraphs (introduction, body 1, body 2, body 3, and conclusion) I'd recommend you to add two more details to your essay. For example,

Schizophrenia is a severe mental illness that deeply affects not only the patient's daily life, but also his family and friends.

paragraph 1 is to develop how schizophrenia affects the patient daily life only. Paragraph 2 is to develop how schizophrenia affects the patient's family and paragraph 3 to develop how it affects his or her family.

Don't forget to put examples, professors love when you put examples.
Good luck, and if you need help, you can ask me.
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Step-by-step explanation:


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Which expression represents the distance between the points (11, 4) and (5,8)?
antiseptic1488 [7]

Answer:

\displaystyle d = 2\sqrt{13}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (11, 4) → x₁ = 11, y₁ = 4

Point (5, 8) → x₂ = 5, y₂ = 8

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                       \displaystyle d = \sqrt{(5-11)^2+(8-4)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                 \displaystyle d = \sqrt{(-6)^2+(4)^2}
  3. [√Radical] Evaluate exponents:                                                                    \displaystyle d = \sqrt{36+16}
  4. [√Radical] Add:                                                                                               \displaystyle d = \sqrt{52}
  5. [√Radical] Simplify:                                                                                         \displaystyle d = 2\sqrt{13}
4 0
3 years ago
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