A number and its absolute value are not equal when the number is less than zero. Since subtracting 2 makes the number less than zero, we know ...
... the number is a non-negative number less than 2. (0 ≤ n < 2)
1 ) V = 1/3 * 18² * 3.14 * 6 = 2,034.72 mm³
2 ) V = 1/3 * 6² * 3.14 * 9 = 339.12 in³
3 ) V = 1/3 * 150² * 3.14 * 240 = 5,652,000 in³
5,652,000 : 12,000 = 471 weeks
Step-by-step explanation:
the average rate of change of a function f in an interval [x-low, x-high] is
(f(x-high) - f(x-low)) / (x-high - x-low)
the year 2000 means t = 2000-1980 = 20
the year 2015 means t = 2015-1980 = 35
so, we have
(A(35) - A(20)) / (35 - 20)
((-0.6(35)² + 37.2×35 + 243) - (-0.6(20)² + 37.2×20 + 243)) / 15
((-735 + 1302 + 243) - (-240 + 744 + 243)) / 15
(810 - 747) / 15 = 63/15 = 4.2
the average change rate between 2000 and 2015 is 4.2.
that means that the use of nuclear energy in the USA increased by 4.2 billions of kilowatt hours per year during that period.
0.132 written in lowercase:
one hundred thirty-two thousandths
zero point one hundred thirty-two
or, even simpler:
zero point one three two
Answer:
- 100
- 489.190
- 10,000
- 48,919,000
Step-by-step explanation:
Each factor of 10 in the divisor causes the decimal point to move 1 place to the left.
a) The decimal point has moved 2 places to the left. The divisor is 10^2 = 100.
b) The divisor is 10^3, so the decimal point will move 3 places to the left.
489.190
c) The decimal point has moved 4 places to the left, so the divisor is 10^4 = 10,000.
d) The divisor is 10^5, so the decimal point in the quotient if 5 places to the left of where it is in the dividend. Moving the quotient's decimal point 5 places to the right gives ...
48,919,000
_____
<em>Additional comment</em>
An exponent signifies repeated multiplication. Here, we're concerned with repeatedly multiplying (or dividing) by factors of 10. The exponent indicates the number of factors: 10·10 = 10^2 = 100. It also matches the number of zeros following the 1 in the product. 1000 = 10^3 has 3 zeros after the 1, for example.
