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2 years ago

How tp find the regression line y on x find out.

Mathematics

1 answer:

dalvyx [7]2 years ago

6 0

Answer:

y=-0.514x+5.8

Step-by-step explanation:

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2x + 4 = 4x how. to solve it

ipn [44]

Answer:

x=2

Step-by-step explanation:

2x+4=4x

-2x -2x

4=2x/2x

4/2=x

x=2

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2 years ago

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Solve for x. solve for x. solve forx.

Veronika [31]

X = 7
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2 years ago

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Which equation is correct? 2x+38) - 5x +4 A 7x - 41 B 7x + 41 C 36x - 2<br>or just write your own

bija089 [108]

Answer:

$-3x+42$

Step-by-step explanation:

$(2x+38) - 5x +4$

$2x+38 - 5x +4$

$2x+38+ - 5x +4$

$2x+-5x+38+4$

$-3x+42$

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3 years ago

What is the solution of the system of equations c + 4d = 8 and c = 4d - 6

Tema [17]

Rewrite the second equation in same form as the first So we have

c + 4d = 8

c - 4d = -6 Now add:-

2c + 0 = 2
2c = 2

c = 1

Now substitute c = 1 in the first equation:-

1 + 4d = 8
4d = 7

d = 7/4 = 1 3/4

Answer c = 1 and d = 1 3/4 Answer

3 0

3 years ago

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If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!

timama [110]

$x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0$

By the quadratic formula,

$x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2$

Then

$(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2$

$\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}$

Multiply numerator and denominator by the denominator's conjugate:

$\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15$

3 0

3 years ago

How tp find the regression line y on x find out.​

How tp find the regression line y on x find out.