as far as I can tell, is just a matter of going around the circle many or infinite times around.
so 6,31° is the first point, the next point will be one-go-around, 6, 31+360 => 6, 391°
then the next will be 6, 391+360 => 6, 751° and so on.
so we can say is (6, 31° ±360°n), n ∈ ℤ.
According to Vieta's formula, if
are solutions of quadratic equation
, then:
In our case:
Answer:
Step-by-step explanation:
Let side of triangle = x
And side of rectangle = y
Perimeter of triangle = 3x
Perimeter of rectangle = 4y
We have two conditions:
Answer:
2
Step-by-step explanation:
2/3 times 4 sets is 8/3, which simplifies to 2 1/3. but you cant have 1/3 of a package so you round to 2
So for this problem, the x-axis is the horizontal line in the center.
Go to where -2 is on the x-axis as shown. Use your finger to trace along since that's usually helpful in finding the point.
Move your finger from -2 on the x-axis to where the solid black line is. On the right side of that, you can see that the y-axis holds the number 2 which is what the y equals for this solid line.
Therefore, the answer should be c.) y = 2
