Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;
Seperate the differential equation and solve for the constant C.
You have 100 rodents when:
You have 1000 rodents when:
Answer:
182.5
Step-by-step explanation:
Here is the equation:
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You need to get "x" by itself so minus 3 from each side
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Divide 8 by 2
÷
x=4
So each 4 is equivalent to 4
Lets check:
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So that means that Marcus practiced the piano for 4 hours and Donnel practiced for 7
Answer:
X = -48
Step-by-step explanation:
Image for explanation