We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
pre-image rectangle has a length of 4 and width of 3. An image rectangle has a length of 2 and width of 1.5.
She could compare the ratios of the sides of the pre-image to the corresponding sides of the image in the proportion StartFraction 3 Over 1.5 EndFraction = StartFraction 4 Over 2 EndFraction.
Step-by-step explanation:
Check the picture below
make sure your calculator is in Degree mode.
Sure 32.144 devided by 9.8
<span>To solve this problem, we can use this formula d = rd (distance = rates x time)
She runs at a speed of 9 mph and walks at a speed of 3 mph.
Her distance running is
d = 9tr
where tr is the time she spends running
Her distance walking is
d = 3tw
where tw is the time she spends walking
The distances are the same so
9tr = 3tw
We also know that the total time is 5 hours
tr + tw = 5
tr = 5-tw
Substitute this value of tr in the first equation
9tr = 3tw
9(5-tw) = 3tw
45-9tw = 3tw
45 = 12tw
3.75= tw
Denise will spend 3.75 hours (3 hours, 45 minutes) walking back and 1.25 hours (1 hour, 15 minutes) running.</span>