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3 years ago

Please help me with this

Mathematics

1 answer:

Annette [7]3 years ago

5 0

Answer:

its A :)

Step-by-step explanation:

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Please help with this question.

andrew11 [14]

Answer:

p3+13=37

We move all terms to the left:

p3+13-(37)=0

We add all the numbers together, and all the variables

p^3-24=0

7 0

4 years ago

A 6-pack of capri-Suns costs $8.80 .How much would a 24-pack cost if the costs are proportional

andrew11 [14]

Now, in a 6-pack, there are 6 bottles, 6-pack.

in a 24-pack, there are 24 bottles, 24-pack.

so, if 6 bottles, cost 8.80, how much will it be for 24 bottles then?

$\bf \begin{array}{ccll}
bottles&price\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
6&8.80\\
24&p
\end{array}\implies \cfrac{6}{24}=\cfrac{8.80}{p}\implies p=\cfrac{24\cdot 8.80}{6}$

5 0

4 years ago

A cylinder’s volume can be calculated by the formula V=pir^2h , where V stands for volume, R for the base radius and H for the c

sasho [114]

Answer:

Step-by-step explanation:

Formula

V pi * r^2 * h

Givens

r = 3 m

h = 6 m

pi = 3.14 when used.

Solution

V = pi r^2 * h

V = pi * 3^2 * 6

V = 9 * 6 * pi

V = 54 * pi Volume in terms of pi

V = 54*3.14 Volume using a value for pi

V = 169.56 to the hundred's place.

3 0

3 years ago

Find the exact value of each trigonometric function for the given angle θ.

Kay [80]

Answer:

$\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.$

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since $\theta=240$ , it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

$\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}$

$\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}$

$\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}$

$\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}$

$\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2$

$\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}$

Therefore, $\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.$

8 0

3 years ago

Which type of function is shown in the graph below?

Lana71 [14]

Answer:

Exponential

Step-by-step explanation:

I have worked with this functions before.

4 0

3 years ago

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