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3 years ago

1 Minutes, 30 seconds

2 answers:

6 0

I think it would be (15-6)*5 because when it says 5 times you would cross out both B and D but then you have to find out what large as 15 minus 6 which i think would be (15-6) so your answer would be C. (15-6)*5

12345 [234]3 years ago

6 0

Assuming you wrote the question correctly, none of the choices are correct. Multiplication takes precedence over subtraction.

(5×15)-6

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Perform each of the following computations using the measured quantities below.

mylen [45]

<h2>Question </h2>

Perform each of the following computations using the measured quantities below.

Write your final answer with the correct number of significant figures in proper scientific notation (one non-zero number to the left of the decimal point).

a. 917.2 + 45.63 = ___________

b. 3.423 x 10^-4 - 6.42 x 10^-3 =_________

<h2>Answer:</h2>

(a) 9.6 x 10²

(b) -6.1 x 10⁻³

<h2>Step-by-step explanation:</h2>

(a) 917.2 + 45.63

<em>First add the two numbers as follows (ensure that the decimal numbers are well aligned);</em>

9 1 7 . 2

+ <u> 4 5 . 6 3</u>

<u></u>

<em>To write the result in a proper scientific notation (one non-zero number to the left of the decimal point), </em>

i. Express the number is standard form

962.83 = 9.6283 x 10²

From the result in (i)

9.6283 = mantissa

10 = base

² = power or exponent.

ii. Express the mantissa of the number in 1 decimal place.

9.6 x 10²

Therefore, the result in the proper scientific notation is <em>9.6 x 10²</em>.

(b) 3.423 x 10⁻⁴ - 6.42 x 10⁻³

Find the difference between the two numbers as follows;

i. Re-write the numbers so that they both have the same exponents:

0.3423 x 10⁻³ - 6.42 x 10⁻³

ii. Factor out 10⁻³

10⁻³(0.3423 - 6.42)

iii. Solve the bracket

10⁻³(-6.0777)

iv. Rewrite the result in (iii)

-6.0777 x 10⁻³

<em>To write the result in a proper scientific notation (one non-zero number to the left of the decimal point), </em>

i. Express the number is standard form

-6.0777 x 10⁻³ [already in standard form]

From the result in (i)

-6.0777 = mantissa

10 = base

⁻³ = power or exponent.

ii. Express the mantissa of the number in 1 decimal place.

-6.1 x 10⁻³

Therefore, the result in the proper scientific notation is -6.1 x 10⁻³.

6 0

2 years ago

Show the work please

Kay [80]

Answer:

1) (x + 3)(3x + 2)

2) x= +/-root6 - 1 by 5

Step-by-step explanation:

3x^2 + 11x + 6 = 0 (mid-term break)

using mid-term break

3x^2 + 9x + 2x + 6 = 0

factor out 3x from first pair and +2 from the second pair

3x(x + 3) + 2(x + 3)

factor out x+3

(x + 3)(3x + 2)

5x^2 + 2x = 1 (completing squares)

rearrange the equation

5x^2 + 2x - 1 = 0

divide both sides by 5 to cancel out the 5 of first term

5x^2/5 + 2x/5 - 1/5 = 0/5

x^2 + 2x/5 - 1/5 = 0

rearranging the equation to gain a+b=c form

x^2 + 2x/5 = 1/5

adding (1/5)^2 on both sides

x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2

(x + 1/5)^2 = 1/5 + 1/25

(x + 1/5)^2 = 5 + 1 by 25

(x + 1/5)^2 = 6/25

taking square root on both sides

root(x + 1/5)^2 = +/- root(6/25)

x + 1/5 = +/- root6 /5

shifting 1/5 on the other side

x = +/- root6 /5 - 1/5

x = +/- root6 - 1 by 5

x = + root6 - 1 by 5 or x= - root6 - 1 by 5

4 0

3 years ago

Which expression is equivalent to 3(-5x + 2) + 20x - 7

lukranit [14]

about Answer: The correct answer would be <u><em>d) 5x - 1</em></u>

Step-by-step explanation:

Simplify or Evaluate the expression and Combine like terms

3(-5x + 2) + 20x - 7

Learn more about how to solve the problem here: brainly.com/question/17829483

7 0

2 years ago

Read 2 more answers

I got the answer as letter C, can someone check me to make sure that is correct? Thank you in advance.

Flura [38]

Answer:

The x's cancel so definitely is choice C: 1/9

Step-by-step explanation:

We have root( 1/(x^2) ) * root ((x^2) / 81)

simplifying this we get as follows:

root( 1/(x^2) ) * root ((x^2) / 81)

= $\sqrt{(1/x^2 )}$ * $\sqrt{(x^2)/81}$

= ( 1/x ) * (x/9)

the x's cancel

= 1/9

choice C 1/9

3 0

3 years ago

Which expression is equivalent to sqrt2/^3sqrt2

zimovet [89]

The given expression is $\frac{\sqrt{2}}{\sqrt[3]{2}}$

This can be simplified using the radical properties as below

$\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\$

Now using exponent properties we can write

$\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}}=2^{\frac{1}{2}-\frac{1}{3}} \\\\\frac{\sqrt{2}}{\sqrt[3]{2}}=2^{\frac{3-2}{6}}=2^\frac{1}{6}\\\\= \sqrt[6]{2}\\$

7 0

3 years ago

Read 2 more answers