Can someone help me with geometry

Mathematics

1 answer:

Vikentia [17]3 years ago

3 0

Answer: 16

-----------------------------------------------------------------------------

Explanation:

The base of the bridge is the lower horizontal segment.

The trapezoid is a combination of a rectangle sandwiched by 2 right triangles. Each triangle is congruent to one another.

The triangles are 45-45-90 triangles indicating "45 degrees 45 degrees 90 degrees" are the three angle measures. Because of this, the legs are congruent. One of the legs is 4, so the other leg must be 4.

The shorter base of the trapezoid is added onto the two horizontal triangular legs to get 8+4+4 = 16

See the attached image to see a further breakdown of the trapezoid

You might be interested in

A stained glass window is going to be installed in a semi-circular opening, which is above a 30 inch wide door. If the stained g

xenn [34]

The answer is $494.55

Let's first imagine a circle and calculate its area and then reduce it in half for the area of a semi-circle. Since this opening is above a 30-inch wide door, the circle will have a diameter of 30 inches.
The area of the circle (A) is:
A = π · r²
where:
π = 3.14
r - radius: r = diameter ÷ 2 = 30 ÷ 2 = 15 inches

So, the area of the circle is:
A = π · r² = 3.14 · 15² = 706.5 inches²

The area of the semicircle is half of the area of the circle:
A1 = A ÷ 2 = 706.5 ÷ 2 = 353.25 inches²

Since the stained glass window costs $1.40 per square inch, for 353.25 square inches it will cost $494.55:
353.25 square inches * 1.40 $/square inch = $494.55

4 0

3 years ago

24 is 3 more than a number p

rewona [7]

Answer: 24 = 3 + P

Step-by-step explanation: 24 is 3 more than a number P can be represented in the equation form of 24 = 3 + P

To solve it:

3 + P = 24

3 - 3 + p = 24 -3

p = 21

7 0

3 years ago

Solve this for Brainliest! See the attachment [Level - GCSE]

madreJ [45]

Answer:

$x = 3 + 4\sqrt{3}$

Step-by-step explanation:

OPQ is a right angle triangle.

Using Pythagoras

$x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0$

Using quadratic formula

$x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}$