<h2>
Answer:</h2>
<u>Distance = 360.55 m</u>
<u>Direction = North-East</u>
<h2>
Step-by-step explanation:</h2>
In the question,
The adventurous dog starts from O, say.
He moves 3 blocks East = 300 m
then,
2 blocks North = 200 m
1 block East = 100 m
1 block North = 100 m
2 blocks West = 200 m
So,
Distance of the Dog's <u>final position</u> from the <u>initial position</u><u>.</u>
OE is given by,
In triangle OLE, using Pythagoras theorem,
<em><u>Therefore, the distance of Dog from the Home is 360.55 m and the direction of Dog from Home is North-East.</u></em>
Answer:
There is no exponential function passing through (1,1) and (5,5).
Step-by-step explanation:
We have the following exponential function
The function passes through these two points:
(1,1): This means that when t = 1, y = 1
(5,5): This means that when t = 5, y = 5.
So
(1,1)
(5,5)
From above, we have that:
1 cannot be equal to 1/5, so this is wrong.
This means that there is no exponential function passing through (1,1) and (5,5).
<u>Answer:</u>
-2
<u>Step-by-step explanation:</u>
We have been given a function f(x)=\frac{-2x}{x+1} and we are asked to find the horizontal asymptote of our given function.
Recalling the rules for a horizontal asymptote:
1. If the numerator and denominator have equal degree, the horizontal asymptote will be the ratio of the leading coefficients.
2. If the polynomial of denominator has larger degree than the numerator, then the horizontal asymptote will be the x-axis or y=0.
3. If the polynomial of numerator has larger degree than denominator, then the function has no horizontal asymptote.
Here, the numerator and denominator are of the same degree. So the horizontal asymptote will be the ratio of the coefficients.
Horizontal asymptote = 
= -2
Answer: it seems to be D, but the equation makes practically no sense!
The value of the factor changes for the different amounts of service years and vacation weeks.
Step-by-step explanation: The equation means that the employee is trying to figure out the value of the "v-factor" for how vacation time is earned.
If you substitute the number of service years into the left side of the "formula" and vacation weeks on the right side, then solve for "v", v(15)=5 you get v= 1/3 or 0.33
If you substitute other numbers, like v(2)=2, so v= 1 then v(30) = 8, v = 4/15 or 0.2667. You see the factor's value decreases. The company is much more generous to to employees with one or two years of service than with the older ones.
