we conclude that the center of the circle is the point (-5, 0).
<h3>How to find the center of the circle equation?</h3>
The equation of a circle with a center (a, b) and a radius R is given by:

Here we are given the equation:

Completing squares, we get:

Now we can add and subtract 25 to get:

Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).
If you want to learn more about circles:
brainly.com/question/1559324
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Answer:
y-4=7(x-1)
Step-by-step explanation:
Hi there!
We are given the slope of the line (7) and the point (1,4) and we need to find the equation in point-slope form.
Point-slope form is given as y-
=m(x-
) where m is the slope and (
,
) is a point
We have all of the needed information for the equation, but let's first label the values of everything in order to avoid confusion
m=7
=1
=4
now substitute into the formula:
<u>y-4=7(x-1)</u>
Hope this helps! :)
Answer:

Step-by-step explanation:
Given that Sara bought a car for $ 23,000 . The interest of loan is 2 .5% . And we need to write a equation g(t) to represent the amount of money that she will owe after t years. Also the amount is compound annually . We know the formula of CI as ,
<u>Compound</u><u> </u><u>Interest</u><u> </u><u>:</u><u>-</u>
Let us take that ,

<u>Put </u><u>on </u><u>the </u><u>respective</u><u> values</u><u> </u><u>:</u><u>-</u>

![\bf \cfrac{(x-2)(x+3)}{2x+2}\implies \cfrac{x^2+x-6}{2x+2}~~ \begin{array}{llll} \leftarrow \textit{2nd degree polynomial}\\ \leftarrow \textit{1st degree polynomial} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{vertical asymptote}}{2x+2=0}\implies 2x=-2\implies x=-\cfrac{2}{2}\implies x=-1](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B%28x-2%29%28x%2B3%29%7D%7B2x%2B2%7D%5Cimplies%20%5Ccfrac%7Bx%5E2%2Bx-6%7D%7B2x%2B2%7D~~%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cleftarrow%20%5Ctextit%7B2nd%20degree%20polynomial%7D%5C%5C%20%5Cleftarrow%20%5Ctextit%7B1st%20degree%20polynomial%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bvertical%20asymptote%7D%7D%7B2x%2B2%3D0%7D%5Cimplies%202x%3D-2%5Cimplies%20x%3D-%5Ccfrac%7B2%7D%7B2%7D%5Cimplies%20x%3D-1)
when the degree of the numerator is greater than the denominator's, then it has no horizontal asymptotes.
quick note:
when the degree of the numerator is 1 higher than the degree of the denominator, then it has an slant-asymptote, so this one has a slant-asymptote.
Answer:
91in in feet 7.5ft
Step-by-step explanation: