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Arisa [49]
2 years ago
5

One of my cats, Apollo, drives a cat car. He used 6/8 of a tank of gas to visit his friends for the weekend, and another 1 half

of a tank to commute to work the next week. He then took another weekend trip and used a 1/4 tank of gas. How many tanks of gas did Apollo use altogether? Tanks of gas
Mathematics
1 answer:
Arlecino [84]2 years ago
7 0

Answer:

Total gas used = 3/2 of a tank of gas

Step-by-step explanation:

Visit to friend = 6/8 of a tank of gas

Commute to work = 1/2 of a tank of gas

Weekend trip = 1/4 of a tank of gas

Total gas used = Visit to friend + Commute to work + Weekend trip

= 6/8 + 1/2 + 1/4

= 6+4+2/8

= 12/8

= 3/2

Total gas used = 3/2 of a tank of gas

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Find the value of y for the given value of x.<br><br> y=2x−3;x=−4
BlackZzzverrR [31]
Y=-11. 2×-4 is -8, and -8-3 is -11.
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3 years ago
Nth term of this sequence:<br><br> -1,3,7,11
AlexFokin [52]

Answer:

What is the sequence? The sequence is +4

Step-by-step explanation:

I don't know if you are asking for the ninth or tenth term of the sequence, but I'll just list them all.

-1,    3,     7,     11,     15,     19,     23,     27,     31,    35, ...

|___||___||___||____||___||____||____||____||____|

 +4     +4    +4    +4     +4      +4     +4       +4      +4

So 31 and 35 are your answer!

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
5 0
3 years ago
Read 2 more answers
Please helpconfused
vodka [1.7K]
The answer is 54in i belive

3 0
3 years ago
Question:
faltersainse [42]

Answer:

The probability that a ship that is declared defecive is sound is 0.375

Step-by-step explanation:

Let P(A|B) denote the conditional probability of A given B. We will make use of the equation

P(A|B) = P(A) × P(B|A) / P(B)

We have the probabilities:

  • P(Declared Defective (detected) | Defective) = 0.95
  • P(not Detected | Defective) = 1-0.95=0.05
  • P(Declared Sound | Sound) = 0.97
  • P(Declared Defective |Sound) = 1-0.97=0.03
  • P(Defective)=0.05
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We can calculate:

P(Declared Defective)= P(Detected | Defective)×P(Defective) + P(Declared Defective |Sound) ×P(Sound) = 0.95×0.05 + 0.03×0.95=0.076

P(S | Declared Defective) =

(P(Sound) × P(Declared Defective | Sound)) / P(Declared Defective)

=0.95×0.03 /0.076 =0.375

3 0
2 years ago
What is the complete factorization of 36y2 − 1?
ludmilkaskok [199]

Answer:

36y² - 1

Factorize

We have the final answer as

(y -  \frac{1}{6} )(36y + 6)

Hope this helps you

3 0
3 years ago
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