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maxonik [38]
3 years ago
15

if there both consecutive doesn't that mean that there both -9 so how is one bigger an one smaller.... ​

Mathematics
1 answer:
MrRissso [65]3 years ago
5 0

Answer:

-14

Step-by-step explanation:

have a great day good luck

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If A = (-2,3), what is ry-axis o D3(A)?<br> A (-6,-9)<br> B (9,-6)<br> C (5,6)<br> D (6,9)
ryzh [129]
C hope it helps you
3 0
3 years ago
Triangles and algebra
Elanso [62]

Hello from MrBillDoesMath!

Answer:

x = 10


Discussion:

A plane triangle contains 180 degrees. Adding the angles in the triangle shown in  #8 gives

(4x + 7) + (3x + 13) + 90 = 180


Note the "right angle" shown in the triangle has been replaced by its 90 degree equivalent in the above equation.

Combining like terms gives


( 4x + 3x) + (7 + 13) + 90 = 180

7x + 20 + 90 = 180 =>                      (subtract 90 from each side)

7x + 20 + 90 - 90 = 180 - 90 = 90  =>

7x +20 = 90  =>                                (subtract 20 from each side)

7x + 20 -20 = 90 -20 =>

7x = 70 =>

x 70/7 =10.



Thank you,

MrB

3 0
3 years ago
What is the process 9.04 turning into 9.10?
Yuki888 [10]
You would add 0.06.

Hope This Helps You!
Good Luck Studying :)
3 0
3 years ago
During a basketball game, Isaias attempted 20 baskets and made 6. What percent of the baskets that he attempted did he make?
aniked [119]

Answer:

30% hope this is rightttt

3 0
3 years ago
Find the 12th term of each sequence. a9= 120, a14=195
Luda [366]
<u>The general formula for an Arithmetic Progression is :</u>

                            \boxed {\boxed {T_n = a_1 + (n-1)d}}


\text {Given that } a_9 = 120,

T_9 = a_1 + (9 - 1)d = 120

a_1 + 8d = 120 \text { ------------------(1)}


\text {Given that } a_{14} = 195,

T_9 = a_1 + (14 - 1)d = 195

a_1 + 13d = 195 \text { ------------------(2)}


<u>Equation (2) - Equation (1) :
</u>
13d - 8d = 195 - 120

5d = 75

d = 15


<u>Substitute d = 15 into Equation (1) :
</u>
a_1 + 8(15) = 120

a_1 = 120 - 120

a_1 = 0

\text {Substitute }a_1 = 0 \text{ and d = } 15,

               \boxed { \boxed { T_n = 15(n -1) }}


<u>Find 12th term :</u>

T_{12} = 15(12 -1) = 165


\boxed {\boxed {\text {Answer: The 12th term is 165.}}}
7 0
3 years ago
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