The tensile strength of spider silk is about 1150 MPa, which is 1.15 x 10^9 N/m².
<span>So given that the diameter of the spider silk is 0.15 mm or 1.5 x 10^-4 m. The cross sectional area is approximately: </span>
<span>A = πr² = (3.14)(1.5 x 10^-4 / 2)² = 1.767 x 10^-8 m² </span>
<span>So this means that the amount of force we can apply before the the silk thread is broken is: </span>
<span>F = PA = (1.15 x 10^9)(1.767 x 10^-8) = 20.32 N </span>
<span>F = mg, so m = F/g = (20.32)/(9.81) = 2.07 kg!!! </span>
Answer:
Step-by-step explanation:
8³+2³=(8+2)(8²-8(2)+2²)
512+8=(10)(64-16+4)
512+8=(10)(64-20)
512+8=(10)(44)
512+8=440
Answer: 4 • (2x - 7) • (x + 3)
Step-by-step explanation:
(4x+12)(2x-7)
8x²-28x+24x-84
8x²-4x-84
Answer:
96 cm^3
Step-by-step explanation:
I hope this helped!
Answer:
B
Step-by-step explanation:
add 7 to get away the 7 on the left hand side
square both side to eliminate square root
