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Juliette [100K]
3 years ago
6

Please help with how I am supposed to do this. D:

Mathematics
1 answer:
kakasveta [241]3 years ago
5 0

Create an inequality:

17+2x>25

(x is the number of goldfish he bought)

Simplify:

2x>8

x>4

Graph is by making a point on the line at 4 with an open circle and include the numbers larger than it (to the right of 4 on the line)

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A piece of paper is four over one thousand inches thick so how many sheets of paper will it take to make a stack 1 inch high
trasher [3.6K]
Keep doing 4 over 1000 until the four reaches the 1000. If four does not go into 1000, then reduce the fraction 4/1000.
6 0
3 years ago
Pair of fractions having sum 1
Strike441 [17]

One such pair is 1/4 and 3/4

1/4 + 3/4 = (1 + 3)/4 = 4/4

= 1

7 0
3 years ago
Read 2 more answers
Which points are exactly 10 units from the point (–8, –2)? Check ALL that apply.
Archy [21]

Answer:

The points that are exactly 10 units from the point (–8, –2) are (2, –2)  and (–8, 8).

Step-by-step explanation:

The distance formula is;

                               d= \sqrt{( x_{2}-x_{1} )^{2}-(y_{2} -y_{1} )^{2}   }

So for distance between: (–8, –2)  and (2, –2) is:

                             d=  \sqrt{( 2-(-8))^{2}-(-2 -(-2) )^{2}   }

                             d= \sqrt{100}

                            d= 10 unit

Similarly for distance between: (–8, –2) and (–8, 8) is,

                                d=  \sqrt{( -8-(-8))^{2}-(8 -(-2) )^{2}   }

                               d= \sqrt{100}

                               d= 10 unit

6 0
4 years ago
I wanted to knwo what two to the third power was please help
nikitadnepr [17]
Eight is the answer.
8 0
4 years ago
Read 2 more answers
A spherical exercise ball has a maximum diameter of 30 inches when filled with air. The ball was completely empty at the start,
Alex73 [517]

Answer:

A) A(t)  =  4500*π  -  1600*t

B) A(4)  =  7730 in³

C) t  =  8,8 sec

Step-by-step explanation:

The volume of the sphere is:

d max  =  30   r max  =  15 in

V(s) =  (4/3)*π*r³      V(s)  =   (4/3)*π* (15)³

V(s) = 4500*π

A)  Amount of air needed to fill the ball A(t)

A(t)  = Total max. volume of the sphere - rate of flux of air * time

A(t)  =  4500*π  -  1600*t    in³

B) After 4 minutes

A(4)  =  4500*π  - 6400

A(4)  =  14130 - 6400

A(4)  =  7730 in³

C)  A(t)  =  4500*π  -  1600*t  

when  A(t) = 0   the ball got its maximum volume then:

4500*π -  1600*t  =  0

t  =   14130/1600

t  =  8,8 sec

8 0
3 years ago
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