Answer:
The function has at least 1 zero within the interval [-2,5].
Step-by-step explanation:
The intermediate value theorem states that, for a function continuous in a certain interval
, then the function takes any value between
and
at some point within that interval.
This theorem has an important consequence:
If a function
is continuous in an interval [a,b], and the sign of the function changes at the extreme points of the interval:
(or viceversa)
Then the function f(x) has at least one zero within the interval [a,b].
We can apply the theorem to this case. In fact, here we have a function f(x) continuous within the interval
[-2,5]
And we also know that the function changes sign at the extreme points of the interval:

Therefore, the function has at least 1 zero within the interval [-2,5], so there is at least one point x' within this interval such that

Answer:
x^2-5x+4
Step-by-step explanation:
(x-3)^2+(x-3)-2
x^2-3x-3x+9+x-3-2
x^2-6x+9+x-5
x^2-5x+9-5
x^2-5x+4
<h2>
Answer:</h2>
Step 1: Determine the formula.
y - y₁ = m(x - x₁)
Step 2: Determine what variables you need.
(x₁,y₁) = a point on the line
m = slope
Step 3: Plug each number in for the variables and you have the completed point-slope form of the equation for the line.

The point-slope form of this line is:
.
See the image for the formula I used.