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Afina-wow [57]
3 years ago
6

What is two over four divided by one over two

Mathematics
2 answers:
Natasha2012 [34]3 years ago
5 0

Answer:

0.25

Step-by-step explanation:

Svet_ta [14]3 years ago
3 0

Answer:

0.25

Step-by-step explanation:

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The figure below is a square. Find the length of side x in simplest radical form with a rational denominator.
telo118 [61]

9514 1404 393

Answer:

  x = (√2)/2

Step-by-step explanation:

The diagonal is √2 times the side length (x), so ...

  1 = x√2

  √2 = 2x . . . . . multiply by √2

  (√2)/2 = x . . . . divide by 2

The side length x is (√2)/2.

3 0
3 years ago
A family has five children. the probability of having a girl is 1/2. what is the probability of having at least 4 girls?
mote1985 [20]
The probability of having at least 4 girls is 0.1875.
6 0
3 years ago
In ΔEFG, g = 6.7 inches, e = 5.9 inches and ∠F=70°. Find the length of f, to the nearest 10th of an inch.
vovangra [49]

Step-by-step explanation:

Using cosine rule,

f² = g² + e² - 2(g)(e)(cosF) = 6.7² + 5.9² - 2(6.7)(5.9)(cos70°)

= 52.6598 in²

Hence f = 7.3 in.

8 0
3 years ago
Read 2 more answers
Cx=d+r solve for x, pls help
Scrat [10]

Answer:

x = d/ C + r/ C

Step-by-step explanation:

The "/" means fraction

Mark me as brainliest please

8 0
3 years ago
BRAINLIESTTT ASAP! PLEASE HELP ME :)
yan [13]

Answer:

<em>P=1620</em>

<em>Third option</em>

Step-by-step explanation:

<u>Horizontal Asymptotes</u>

A given function is said to have a horizontal asymptote in y=a, if:  

\displaystyle \lim _{x\rightarrow -\infty }f(x)=a

Or,

\displaystyle \lim _{x\rightarrow +\infty }f(x)=a

For the given function, the population of the species of bird is given by :

\displaystyle p(t)=\frac{1620}{1+1.15e^{-0.042t}}

Where t is the time in years. To find the horizontal asymptote, we should compute both limits to check if they exist.  

\displaystyle \lim _{x\rightarrow +\infty }\frac{1620}{1+1.15e^{-0.042t}}=\frac{1620}{1+0}=1620

When t tends to plus infinity, P tends to 1620 .

The second asymptote is computed by:

\displaystyle \lim _{x\rightarrow -\infty }\frac{1620}{1+1.15e^{-0.042t}}=\frac{1620}{1+\infty}=0

When t tends to minus infinity, P tends to zero. Since the domain of P is t\geq 0, this asymptote is not valid, thus our only asymptote is

\boxed{P=1620}

6 0
3 years ago
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