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kondaur [170]
2 years ago
12

15. If R is the midpoint of OS, OR = 8x - 51 and RS = 3x - 6, find QS.

Mathematics
2 answers:
Vikki [24]2 years ago
8 0

Answer:

if you mean find OS, then:

OS = 42

Step-by-step explanation:

if you mean find OS, then:

8x-51 = 3x-6

5x = 45

x = 9

OS = 2(3x-6)

OS = 6x-12

substitute for x

OS = 6(9)-12 =42

OverLord2011 [107]2 years ago
7 0

Step-by-step explanation:

ok si esoes la respuesta corecta yo les digo niños por que yo soy una profesora de mate y se mas de mate que ustedes

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The shadows of two vertical poles were measured at the same time to be 6m and 15m long. If the first pole is 8cm long, find the
son4ous [18]

Answer:

20 cm

Step-by-step explanation:

Shadow of vertical poles : 6m ; 15m

Length of poles : 8cm ; h

8cm long pole = shadow length, 6m

h cm long pole = shadow length, 15 m

Using cross multiplication :

8cm * 15 m = h cm * 6m

120 = 6h

h = 120 / 6

h = 20 cm

Height of second pole = 20cm

8 0
3 years ago
Choose ALL possible answers
muminat
Select all the correct answers:
1) Yes

2) No
x=8→h(8)=2(8)^2+5(8)+2=2(64)+40+2=128+40+2→h(8)=170
x=8→f(8)=3^8+2=6,561+2→f(8)=5,563>170=h(8)

3) Yes

4) No

5) Yes
rg=[g(3)-g(2)]/(3-2)=[g(3)-g(2)]/1→rg=g(3)-g(2)
g(3)=20(3)+4=60+4→g(3)=64
g(2)=20(2)+4=40+4→g(2)=44
rg=64-44→rg=20

rf=f(3)-f(2)
f(3)=3^3+2=27+2→f(3)=29
f(2)=3^2+2=9+2→f(2)=11
rf=29-11→rf=18

rh=h(3)-h(2)
h(3)=2(3)^2+5(3)+2=2(9)+15+2=18+15+2→h(3)=35
h(2)=2(2)^2+5(2)+2=2(4)+10+2=8+10+2→h(2)=20
rh=35-20→rh=15

rg=20>18=rf
rg=20>15=rh

6)  No
x=4→g(4)=20(4)+4=80+4→g(4)=84
x=4→h(4)=2(4)^2+5(4)+2=2(16)+20+2=32+20+2→h(4)=54
x=4→f(4)=3^4+2=81+2→f(4)=83>54=h(4)
f(4)=83<84=g(4)
7 0
2 years ago
How do I find the indicated derivative?
sergey [27]
Multiply the fraction by both things in the parenthesis.
8 0
3 years ago
Please help me with this question and thank you for your help
Volgvan

The question is asking for the pattern of change within the given numbers. As you can see, the number decreases by 0.02 from left to right. Therefore, D is the correct answer. The whole number and tenths place remains constant as the hundredths place lowers by 2.

4 0
2 years ago
Read 2 more answers
Determine the measure of ∠Q, rounded to the nearest tenth of a degree.<br> images attached.
const2013 [10]

Answer:

D

Step-by-step explanation:

Using the Sine rule in Δ QRS , that is

\frac{q}{sinQ} = \frac{r}{sinR} , that is

\frac{15}{sinQ} = \frac{12}{sin50.1} ( cross- multiply )

12× sinQ = 15 × sin50.1° ( divide both sides by 12 )

sinQ = \frac{15sin50.1}{12} , thus

Q = sin^{-1} ( \frac{15sin50.1}{12} ) ≈ 73.5° ( to the nearest tenth )

8 0
3 years ago
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