According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

Here, n is equal to 66 and by substituting the value to the equation we get:

k = 7.0444
k ≈ 7
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Answer:
15 sqrt 2
Step-by-step explanation:
Use Pythagorean Theorem
a^2 + b^2 = c^2
15^2 + 15^2 = c^2
225 + 225 = 450
Find prime factors of the sq rt of 450
450 = 2 * 3 * 3 * 5 * 5
15 sqrt 2
Answer:
A but I'm not so sure
Step-by-step explanation:
Answer:
The answer is below.
Step-by-step explanation:
The GCF is 2z because it is the biggest number that can be factored out of both numbers. Also, since the 8z has no exponent, the GCF of 2z doesn't need one either.
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