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AlladinOne [14]
3 years ago
8

The bill for lunch was $7

Mathematics
2 answers:
mafiozo [28]3 years ago
6 0
Ok what is the question lol
Angelina_Jolie [31]3 years ago
5 0

Answer:

thank you! very cool!

Step-by-step explanation:

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Place is highest to lowest 3/4 84% 1/3 0.82
sesenic [268]

ANSWER

84%,0.82,¾,⅓

EXPLANATION

Convert everything to decimals.

\frac{3}{4}  = 0.75

84\% = 0.84

\frac{1}{3}  = 0.333....

The last one is already in decimals.

0.82

We can now see clearly, that

0.84  \: > \:  0.82 \:  >  \: 0.75  \: >  \: 0.3333...

This implies that,

84\% \: > \:  0.82 \:  >  \:  \frac{3}{4}   \: >  \:  \frac{1}{3}

Hence from highest to least, we have

84%,0.82,¾,⅓

4 0
4 years ago
What is a measurement<br>​
ad-work [718]

Answer:

Its the instrument that measures unknown quality of goods.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A drug used to relieve anxiety and nervousness has a half-life of 16 hours. if a doctor prescribes one 2.8-milligram every 24 ho
dlinn [17]

After 24 hours, 35.4% of the initial dosage remains on the body.

<h3>What percentage of the last dosage remains?</h3>

The exponential decay is written as:

f(x) = A*e^{-k*x}

Where A is the initial value, in this case 2.8mg.

k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:

k = ln(2)/16h

Replacing all that in the above formula, and evaluating in x = 24 hours we get:

f(24h) = 2.8mg*e^{-24h*ln(2)/16h} = 0.9899 mg

The percentage of the initial dosage that remains is:

P = \frac{0.9899mg}{2.8mg}*100\% = 35.4\%

If you want to learn more about exponential decays:

brainly.com/question/11464095

#SPJ1

8 0
2 years ago
Helo helo hell hell help
Ymorist [56]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
a man is standing on top of a cliff, 80 high, the angle of depression to a boat is 60° . calculate the distance of the boat from
Maurinko [17]

Answer:

20 :3

Step-by-step explanation:

Da distance is 20

80 - 60 = 20 BOOM PEEPS

3 0
3 years ago
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