Answer:
I'm pretty sure it is (a)
Answer: Hello your question is poorly written attached below is the complete question
answer:
0.1515
Step-by-step explanation:
Number of bets = 200
mean number of losses = $0.2
Standard deviation = $2.74
<u>Determine P ( winning after 200 bets ) </u>
Average of 200 bets > 0. i.e. P( X > 0 )
considering normal distribution : μ = -0.2 , б = 2.74 , n = 200
applying Z - distribution
z = 0 - ( - 0.2 ) / ( 2.74 / √200 ) ≈ 1.03
∴ P ( z > 1.03 ) = 1 - P ( z < 1.03 )
= 1 - 0.8485 ( value gotten from z-table )
= 0.1515
Answer:
28%
Step-by-step explanation:
Let number of children be 2x, then number of adults be 3x
Total number is 5x
Let number of children under 10 be 7y, number of children be 3y,
then total number of children is 10y
so 2x = 10y, x = 5y, y/x = 1/5
younger children = children under 10, number is 7y
so the % is 7y/5x = 7/5 * y/x = 7/5 * 1/5 = 7/25 = 28/100 = 28%
Answer:
29
Step-by-step explanation:
180-151=29
Hey!
Hope this helps...
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The correct answers are A, B, D, and E