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ZanzabumX [31]
2 years ago
14

What’s the function of f(x)=-2/3x -7 ?

Mathematics
1 answer:
Blababa [14]2 years ago
3 0

Answer:

F(x) = -1/3 x^2 - 7x + C

You might be interested in
What is the solution of this equation? -1/2n2+18=0
SashulF [63]

Answer:

n=-6\text{ or } n=6

Step-by-step explanation:

So we have the equation:

-\frac{1}{2}n^2+18=0

Subtract 18 from both sides. The left cancels:

-\frac{1}{2}n^2=-18

Multiply both sides by -2. The left cancels again:

n^2=36

Take the square root of both sides:

n=\pm\sqrt{36}

Since we're taking the square root, we need to use plus-minus.

Evaluate:

n=\pm 6

So, the solutions are -6 or 6.

5 0
3 years ago
Daniel worked for 213 hours and earned $18.20.
OleMash [197]

Answer:

2 1/3hrs→ $18.20

1 hr→ $7.80

5 1/4hrs→ $7.80x5 1/4= $40.95

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Order of Operations- -6+(-30) divided by 5-(-2). Explain step by step
Reil [10]

Answer:

-36/7 or -5.14287

Step-by-step explanation:

so I would get rid of parentheses you do not need them

\frac{-6+-30}{5--2}=\frac{-36}{7}(because when two negative come before two numbers like -x-y they are being added but negative is present to the result of the sum, when one negative sign comes after a number and the other negative sign comes before a number, like x--y they are being added as well but negative is not present to the result of the sum)

-36/7=-5.1428

hope this helps!

7 0
3 years ago
When using fraction strips ,how do you know that 2 fractions are equivalent
Zigmanuir [339]
When the longer strip is on top and the litter strips fit perfectly under the longer one. For example, the fraction 1/3 and 3/6. One longer strip will be on the top representing 6. Then 3 litter 3s will be under that perfectly
5 0
3 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
2 years ago
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