The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches
Answer:
The length of each edge is 2in.
Step-by-step explanation:
This is because 2x2x2=8. 2x2 is 4 and 4x2 is 8.
the answer is y=2x-3
You can look at my work if you really need to
The 4th roots of a^12 = a^3 so we can take out a^3
4th root of 144 = 4th root of 9 * 2 so we can also take out 2
The answer is the first choice.
Answer:
Step-by-step explanation: