Find the lettered angles.

An inequality for y greater than or equal to 4

zalisa [80]

The inequality statement, “An inequality for y greater than or equal to 4” can be written as:

y ≥ 4

Please mark my answers as the Brainliest if you find my explanations helpful :)

3 0

2 years ago

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What is the probability that a randomly selected senator is a Democrat or is up for reelection in November 2014? (Enter your pro

Vesna [10]

Answer: 20/33

Step-by-step explanation:

According to the table of statistics given for the politicians

number of Dem. Senator = 20

number of Rep. Senator = 13

Total for Senators = 33

Let E be the event,

The required probability is:

P(E) = P(Dem)

= 20/33

3 0

2 years ago

Shakira went bowling with her friends .she paid $3 to rent shoes and then $4.75 for each game of bowling.if she spent a total of

zloy xaker [14]

Shakira bowled around 4 games

3 0

3 years ago

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4. A fruit vendor packed 100 apples each in 64 baskets. Later, he found some apples were left unpacked. So he packed 30 more app

topjm [15]

Answer:

Here is the answer

Step-by-step explanation:

Apples in 1 baskets=100

Apples in 64 baskets=100*64-6400

apples (before adding 30 apples in each

basket).... ..(1)

Some apples left unpacked

So he added 30 apples to each

Total apples added by him- 30*64(in each basket*no of baskets)

= 1920 apples

.(2)

So total no apples eq(1)+eq(2)

= 6400 apples + 1920 apples

=8320 apples packed in total

Therefore the total no. of apples packed were 8320 apples.

Hope this helps

Thanks

4 0

1 year ago

Given the following right triangle, find cose, sine, tane sececsce, and cote. Do not

IgorLugansk [536]

Step-by-step explanation:

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=4,\ hypotenuse=10$

Substitute:

$4^2+leg^2=10^2$

$16+leg^2=100$ <em>subtract 16 from both sides</em>

$leg^2=84\to leg=\sqrt{84}\\\\leg=\sqrt{(4)(21)}\\\\leg=\sqrt4\cdot\sqrt{21}\\\\leg=2\sqrt{21}$

$sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\cotangent=\dfrac{adjacent}{opposite}\\\\secant=\dfrac{hypotenuse}{adjacent}\\\\cosecant=\dfrac{hypotenuse}{opposite}$

Substitute:

$hypotenuse=10,\ opposite=4,\ adjacent=2\sqrt{21}$

$\sin\theta=\dfrac{4}{10}=\dfrac{2}{5}\\\\\cos\theta=\dfrac{2\sqrt{21}}{10}=\dfrac{\sqrt{21}}{5}\\\\\tan\theta=\dfrac{4}{2\sqrt{21}}=\dfrac{2}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{2\sqrt{21}}{21}\\\\\cot\theta=\dfrac{2\sqrt{21}}{4}=\dfrac{\sqrt{21}}{2}\\\\\sec\theta=\dfrac{10}{2\sqrt{21}}=\dfrac{5}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{5\sqrt{21}}{21}\\\\\csc\theta=\dfrac{10}{4}=\dfrac{5}{2}$

5 0

3 years ago