Which of the following best represents a change in elevation of 0 feet?

The hexadecimal number is 0xFEE. what will be the octal number of this?

Vikentia [17]

Answer:

0xFEE₁₆ = 7756₈

Step-by-step explanation:

Convert the hexadecimal number to decimal first

0xFEE

E = 14

F = 15

Then convert them to binary

$\frac{14}{2}=7$

Remainder = 0

$\frac{7}{2}=3$

Remainder = 1

$\frac{3}{2}=1$

Quotient = 1

Remainder = 1

$\frac{15}{2}=7$

Remainder = 1

$\frac{7}{2}=3$

Remainder = 1

$\frac{3}{2}=1$

Quotient = 1

Remainder = 1

0 F E E

0000 1111 1110 1110

Take groups of three

and multiply with $2^n$ where n is the place of the digit

111 111 101 110

4,2,1 4,2,1 4,2,1 4,2,1

4+2+1 4+2+1 4+0+1 4+2+0

7756

So, 0xFEE₁₆ = 7756₈

8 0

4 years ago

Which of the following graphs shows the solution set for the inequality below? 3|x + 1| < 9

Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

$f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}$ .

This definition of the absolute function can be explained geometrically to be similar to the straight line $\textbf{\textit{y}} \ = \ \textbf{\textit{x}}$ , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line $\textbf{\textit{y}} \ = \ \textbf{\textit{x}}$ where $\textbf{\textit{x}} \ < \ 0$ (shown as the orange dotted line), the segment of the line is reflected across the x-axis.

First, we simplify the expression.

$3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3$ .

We, now, can simply visualise the straight line, $y \ = \ x \ + \ 1$ , as a line having its y-intercept at the point $(0, \ 1)$ and its x-intercept at the point $(-1, \ 0)$ . Then, imagine that the segment of the line where $x \ < \ 0$ to be reflected along the x-axis, and you get the graph of the absolute function $y \ = \ \left|x \ + \ 1 \right|$ .

Consider the inequality

$\left|x \ + \ 1 \right| \ < \ 3$ ,

this statement can actually be conceptualise as the question

$``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}"$ .

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

Case 1 (when $x \ \geq \ 0$ )

$x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2$

Case 2 (when $x \ < \ 0$ )

$-(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4$

*remember to flip the inequality sign when multiplying or dividing by

negative numbers on both sides of the statement.

Therefore, the values of x that satisfy this inequality lie within the interval

$-4 \ < \ x \ < \ 2$ .

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0

3 years ago

Convert the equation you found, T = A3/2, into a form without any rational exponents.

solniwko [45]

Y = mx + bDomainAll the X values in a functionRangeAll the Y values in a function

6 0

3 years ago

Read 2 more answers

Solve for 2.

Step2247 [10]

Answer:

(3x – 6)(-x + 3) = 0

=> 3x - 6 = 0 => x = 6/3 = 2

and

=> -x + 3 = 0 => x = 3

Hope this helps!

:)

5 0

3 years ago

Point T has coordinates (10,20). To calculate the coordinates of point T′ in the image,

Hatshy [7]

Answer: $T'(18,36)$

Step-by-step explanation:

For this exercise it is important to know the definition of "Dilation".

A Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) and the Pre-Image (The original figure before the transformation) have the same shape but have different sizes.

If the Dilation is centered at the origin, and knowing the scale factor of $\frac{9}{5}$ , you need to multiply each coordinate of the point T by the scale factor in order to find the coordinates of the Image T'.

Knowing that the point T has the following coordinates:

$T(10,20)$

You get that the coordinates of the Image T' are the shown below:

$T'=(\frac{9}{5}*10,\frac{9}{5}*20)\\\\T'=(18,36)$

6 0

4 years ago