The graph is Parabola or Graph of Quadratic Function.
The graph has minimum value, not maximum. So ( A ) is not correct for maximum part.
B is not correct for exponential part.
also C is not correct for discrete part as Quadratic graph is continuous.
So the answer is D.
Answer:
Vertical angle=9.5°
Time to reach maximum height = 1.24seconds
Step-by-step explanation:
The maximum distance x is reached when rope swings to a maximum height, maximum height is gotten from the equation KE= 1/2MU^2 = MgH = MgL= Mgl(1- cos theta.
Where theta is the vertical angle, U=2m/s and L= 15m
2gl -2glcostheta=U^2
2gl U^2=2gl cos theta
But theta= Acos(1- U^2)/2gl
Acos(1-/(2×9.8×15)
Theta =9.5°
Maximum height li given by
Lsintheta
But X= UxT
T=X/UX= Lsintheta/U = 15sin9.5 /2 =1.24seconds
Answer:
i believe the answer is 63
Step-by-step explanation:
Answer:
y = 4x + -3
Step-by-step explanation:
1. Write the formula for slope y = mx + b
2. Find a point anywhere on the graph and use rise over run. Find slope by counting how many times you rise up.
3. You rose 4. The variable m is for the slope of a line so fill in the number 4. y = 4x + b
4. The variable b represents the y intercept and the y intercept is where the line crosses over the y axis. So that would be -3
5. Fill in the variable b with -3
6. Finally you would have y = 4x + -3
Hope this is right and hope this helps in the future!
