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3 years ago

What experience did ramses have that made him a great military leader?

Mathematics

1 answer:

ASHA 777 [7]3 years ago

8 0

Answer:

During his reign as pharaoh, Ramses II led the Egyptian army against several enemies including the Hittites, Syrians, Libyans, and Nubians. He expanded the Egyptian empire and secured its borders against attackers. Perhaps the most famous battle during Ramses' rule was the Battle of Kadesh.

Step-by-step explanation:

That's a couple reasons.

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Tak purchased 478 pounds of brown sugar. Each pound of the sugar equals 214 cups. What is the best estimate of the number of cup

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Carlos and Maria drove a total of 197 miles In 3.8 hours. Carlos drove the first part of the trip and averaged 55 miles per hour

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Answer:

1.5 hours

Step-by-step explanation:

Carlos = x

Maria = y

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3 years ago

Solve the following system of equations. x − 2y = 5 −3x + 2y = 7

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3 years ago

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From Alexa's eyesight to the top of the tree has an angle of 56.789 degrees and its distance of 23.45 feet. Match the following

Marat540 [252]

Answer:

Distance between Alexa and tree = 12.844 ft

Height of tree = 19.620 + height of eyesight from ground

Perimeter of triangle formed = 55.914 ft

Step-by-step explanation:

From the given data, the attached image is drawn ( refer attachment)

Assume

Height of eye line as $h_{A}$ , height of tree as $h_{T}$ , distance of tree from Alexa as X and vertical distance between eye line and top of tree is y.

To find: distance of tree from Alexa

consider triangle ATE. Here

X = 23.45 * cos ( $56.789^{o}$ ) = 12.844 ft

y = 23.45 * sin ( $56.789^{o}$ ) = 19.620 ft

Hence distance of tree from Alexa = 12.844 ft

Height of tree $h_{T}$ = y + $h_{A}$

= 19.620 + $h_{A}$

Perimeter of triangle = X + Y + 23.45 ft

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= 55.914 ft

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3 years ago

A total of $6000 was invested, part of it at 3% interest and the remainder at 8%. If the total yearly interest amounted to $380,

Nastasia [14]

$ 2000 is invested at 3 % interest and $ 4000 is invested at 8 % interest

Solution:

Given that, total of $6000 was invested

Let "x" be the amount invested at 3 % interest

Then, (6000 - x) is the amount invested at 8 % interest

Given that,

The total yearly interest amounted to $380

Then, we can frame a equation as:

$x \times 3 \% + (6000 - x) \times 8 \% = 380$

Solve the above expression for "x"

$x \times \frac{3}{100} + (6000-x) \times \frac{8}{100} = 380\\\\0.03x + (6000-x) \times 0.08 = 380\\\\0.03x + 480 - 0.08x = 380\\\\-0.05x = -100\\\\\text{Divide both sides by -0.05 }\\\\x = 2000$

Thus, $ 2000 is invested at 3 % interest

(6000 - x) = 6000 - 2000 = 4000

$ 4000 is invested at 8 % interest

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4 years ago