The probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.
<u>Step-by-step explanation:</u>
- There are 1 red ball and 4 white balls in a box.
- The total number of balls in the box = 1 red + 4 white = 5 balls.
The two balls are drawn without replacement.
<u>Drawing the first ball :</u>
The first draw should be a red ball.
The probability to get a red ball = No.of red balls / Total balls in the box.
We know that, No. of red balls is 1 and total balls in the box is 5.
P(red ball) = 1/5
<u>Drawing the second ball :</u>
The second draw should be a white ball.
The probability to get white ball = No.of white balls / Total balls in the box.
We know that,
No. of white balls is 4.
The total balls in the box after the first draw will be 4 balls.
P(white ball) = 4/4
The probability of getting a red ball on the first drawn and a white ball on the second draw = P(red ball) × P(white ball)
⇒ (1/5) × (4/4)
⇒ 4/20
⇒ 1/5
Therefore, the probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.
The correct answer is letter D
Just believe me thats the correct answer
Answer:
x = -10
Step-by-step explanation:
Step 1: Write equation
180 + 8x = 160 + 6x
Step 2: Solve for <em>x</em>
- Subtract 6x on both sides: 180 + 2x = 160
- Subtract 180 on both sides: 2x = -20
- Divide both sides by 2: x = -10
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
180 + 8(-10) = 160 + 6(-10)
180 - 80 = 160 - 60
100 = 100
Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!
You need to know three exponent rules to simplify these expressions:
1)
The
negative exponent rule says that when a
base has a negative exponent, flip the base onto the other side of the
fraction to make it into a positive exponent. For example,

.
2)
Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example,

.
3) The
zero exponent rule<span> says that any number
raised to zero is 1. For example,

.
</span>
Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is

. The x-values are:
<span>
1) x = 0</span>Plug this into

to find letter a:

<span>
2) x = 2</span>Plug this into

to find letter b:

<span>
3) x = 4</span>Plug this into

to find letter c:

<span>
Problem 2
</span>The x-values are in the left column. The title of the right column tells you that the function is

. The x-values are:
<span>
1) x = 0</span>Plug this into

to find letter d:

<span>
2) x = 2
</span>Plug this into

to find letter e:

<span>
3) x = 4
</span>Plug this into

to find letter f:

<span>
-------
Answers: a = 1b = </span>

<span>
c = </span>
d = 1e =
f =