All categories

2 years ago

A van is traveling 1.5 km per minute. How fast is the van traveling in miles per hour?

Mathematics

2 answers:

stellarik [79]2 years ago

5 0

Answer: 1.5 KPM = 56.25 MPH

Step-by-step explanation:

1.5 divided by 1.6

equals 0.9375

then times that by 60

and get 56.25

ipn [44]2 years ago

3 0

Answer:

55.9234

Step-by-step explanation:

1.5*60=90

90km=(x) miles

You might be interested in

Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr

Minchanka [31]

Answer:

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". The margin of error is the range of values below and above the sample statistic in a confidence interval. Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". [tex]p_1$ represent the real population proportion for 1

$\hat p_1 =0.768$ represent the estimated proportion for 1

$n_1=92$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =0.646$ represent the estimated proportion for 2

$n_2=95$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

$ME= \frac{0.2753-(-0.0313)}{2}=0.1533$

And we know that the margin of erro is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

We have all the values except the value for $z_{\alpha/2}$

So we can find it like this:

$0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}$

And solving for $z_{\alpha/2}$ we got:

$z_{\alpha/2}=2.326$

And we can find the value for $\alpha/2$ with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98$ or 98%

7 0

2 years ago

It takes 3 pieces of wood to make a bird house. Marina has 21 pleces of wood. She uses this problem to find out how many bird ho

xxMikexx [17]

She can find out answer by dividing 21÷3 and the answer is 7

She can make 7 bird house

7 0

2 years ago

Read 2 more answers

I’m still confused on how to do this even though it was explained to me please help :(

valkas [14]

$a. \: \hat{D}=\hat{C}=64° \\ b. \stackrel\frown{BF}=2\hat{C}=2\times 64°=128° \\ c. \: \hat{E} = \hat{C}=64° \\ d. \stackrel \frown{CBF} = 2\widehat{CEF}=2\times 90°=180° \\ e. \: \widehat{BAF} = 2\hat{C} = 2\times 64°=128° \\ f. \: \widehat{BAC} = \widehat{CAF}-\widehat{BAF}=180°-128°=52°$