Answer:
The two scenarios differ.
P(Scenario A) = 0.107
P(Scenario B) = 0.265
Step-by-step explanation:
The two scenarios are different because for the second one you are alredy assuming that the first 3 cards are not hearths, and for that reason, B is more likely to happen that A.
For B to happen, you need to notice that since you remove 3 cards from your deck that are not hearts, then your deck has only 49 cards, and 13 of them are hearts. The probability for a heart to show up is, as a result 13/49 = 0.265 because you have 13 favourable cases from 49 possible.
For A, you need the first card to be anything but a heart. Since 13 cards of the deck are herts, 39 are not, and the probability of that hapening is 39/52 = 3/4. After you remove your first card, the probability of the second one not being heart is 38/51, and the probability for the third one is 37/50 (you are removing one favourable case and one case for the total of cases each time). The probability for the fourth card being a heart assuming that the first three are not was calculated before and it gives us a result of 13/49.
Multiplying everything, we obtain that
P(A) = 3/4*38/51*37/50*13/49 = 0.107.
as y varies directly with x, the following equation can be established.
y = a * x
from the condition given by the question, we can know that
7.5 = a * 3
a = 7.5 / 3 = 2.5
thus, we can infer that the equation is
y = 2.5 * x
Answer:
24
Step-by-step explanation:
Average = total number of coins / number of students
If the mean number of coins with boys is 14, the total number of coins held by boys = 14 x 9 = 126
The total number of coins held by the students = total number of children x average number of coins held by the children
15 x 18 = 270
The total number of coins held by girls = 270 - 126 =144
The mean number of coins for the girls = 144 / 6 = 24
Answer:
57
Step-by-step explanation:
