Assuming that you're talking about a standard deck of 52 cards, there are 4 tens and 4 aces.
So, at the beginning, you have probability 4/52=1/13 to draw a ten.
You replace, and you have an identical probability to draw an ace (you still have 4 favourable cases over 52 total cases).
Multiply the two probabilities to find the answer:
Gina surveyed students about their lunch time preference. Out of 50 students, 20 prefer eating lunch at 11:00am, 15 prefer eating at 11:15a.m., 10 prefer eating at 11:30a.m. , and 5 have no preference. Based on the information, what is the probability that a student chosen at random has no lunch time preference?
V=(4/3)(pi)(r^3)
r=7
Hope this’ll help
Answer:
C) Apply the distributive property
