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Scilla [17]
3 years ago
8

A __________ is formed when tectonic plates collide.

Advanced Placement (AP)
1 answer:
Alborosie3 years ago
8 0

convergent plate boundary. Usually, one of the converging plates will move beneath the other, a process known as subduction. Deep trenches are features often formed where tectonic plates are being subducted and earthquakes are common.

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How might the following concepts make the trip enjoyable for the sisters?
amm1812

The following concepts make the trip enjoyable for the sister with the option suitable papillae

Explanation:

  • Its is about two sisters, where the elder sister takes rose to watch movie, and keeps some cash to buy food to eat.
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  • papillae as known as the mucous membranes which are formed by cells bulging underneath tongue. Papillae are the little bumps, which  makes the tongue look rough.
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4 0
3 years ago
Ginagawa ko naman ang lahat he.pero bakit kahit anong gawin ko...laging kulang?laging kulang
Shtirlitz [24]

Answer:

laging kulang

Explanation:

laging kulang

6 0
3 years ago
HELP PLZZ????
guajiro [1.7K]

Answer:

d. The first broadcast of the Grand Ole Opry

Explanation:

The first broadcast of the Grand Ole Opry happened before all the options given in the question.

The Grand Ole Opry is a stage dance for country music lovers. It was first founded on November 28, 1925, by George D. Hay as a one-hour radio "barn dance" on WSM. The first broadcast was the longest lived broadcast where the famous cowboy got the chance to showcase his skills.

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5 0
4 years ago
For the equilibrium: 2 NO​ (g) ​ ⇌ N​ 2(g)​+ O​ 2(g)​at 300 K, the equilibrium constant, Kc, is 0.185. If 1.45 moles each of N​
Brrunno [24]

Answer: The concentrations of N_2,O_2\text{ and }NO at equilibrium are 0.112 M, 0.112 M  and 0.260 M

Explanation:

Moles of N_2 = 1.45 mole

Moles of  O_2 = 1.45 mole

Volume of solution = 6.00 L

Initial concentration of N_2 = \frac{moles}{Volume}=\frac{1.45mol}{6.00L}=0.242M

Initial concentration of O_2 = \frac{moles}{Volume}=\frac{1.45mol}{6.00L}=0.242M

The given balanced equilibrium reaction is,

           2NO(g)\rightleftharpoons N_2(g)+O_2(g)

Initial conc.          0 M             0.242 M              0.242 M  

At eqm. conc.     (2x) M      (0.242-x) M        (0.242-x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[N_2]\times [O_2]}{[NO]^2}  

Now put all the given values in this expression, we get :

0.185=\frac{(0.242-x)^2}{(2x)^2}

By solving the term 'x', we get :

x = 0.130

Thus, the concentrations of at equilibrium are :

Concentration of = (0.242-x) M  = (0.242-0.130) M = 0.112 M

Concentration of = (0.242-x) M  = (0.242-0.130) M = 0.112 M

Concentration of = 2x M = = 0.260 M

7 0
3 years ago
What are four phases in doing research? Describe each phase.
TiliK225 [7]
Determine the problem
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Use the library catalog
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3 years ago
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