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emmasim [6.3K]
3 years ago
12

Jared consuela and Reggie have an ant farm Jared collected 25/100 of the ants from the ant farm consuela collected 6/10 of the a

nts what fraction of the ants did Jared and consuela collected together
Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0

Answer:

17/20

Step-by-step explanation:

\frac{25}{100} + \frac{6}{10}

to solve this multiply both fractions by 100

(25 + 60) / 100 = 85/100

we need to find the lowest common multiple

Both the numerator and denominator can be divided by 5 = 17/20

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Help plz!!!!!!!!! (pic below)
viktelen [127]

Answer:

k = 13.5

Step-by-step explanation:

Since 3 * 3 = 9

And 3 * 4 = 12

Then 3* 4.5 = 13.5

As the statement goes, "Triangle XYZ is similar to Triangle ABC."

4 0
3 years ago
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|3p+5|=6p−1<br> need answer ASAP
kolbaska11 [484]

Answer:

p=2

Step-by-step explanation:

5 0
4 years ago
In an experiment, a fair coin is tossed 13 times and the face that appears (H for head or T for tail) for each toss is recorded.
zalisa [80]

Answer:

1) 1 element

2) 13 elements

3) 22 elements

4) 40 elements

Step-by-step explanation:

1) Only one element will have no tails: the event that all the coins are heads.

2) 13 elements will have exactly one tile. Basically you have one element in each position that you can put a tail in.

3) There are {13 \choose 2} = 78 elements that have exactly 2 tails. From those elements we have to remove the only element that starts and ends with a tail and in the middle it has heads only and the elements that starts and ends with a head and in the 11 remaining coins there are exactly 2 tails. For the last case, there are {11 \choose 2} = 55 possibilities, thus, the total amount of elements with one tile in the border and another one in the middle is 78-55-1 = 22

4) We can have:

  • A pair at the start/end and another tail in the middle (this includes a triple at the start/end)
  • One tail at the start/end and a pair in the middle (with heads next to the tail at the start/end)

For the first possibility there are 2 * 11 = 22 possibilities (first decide if the pair starts or ends and then select the remaining tail)

For the second possibility, we have 2*9 = 18 possibilities (first, select if there is a tail at the end or at the start, then put a head next to it and on the other extreme, for the remaining 10 coins, there are 9 possibilities to select 2 cosecutive ones to be tails).

This gives us a total of 18+22 = 40 possibilities.

5 0
3 years ago
Find the missing side length in the image attached.
Aleks [24]

Answer:

? = 56.

Step-by-step explanation:

In the problem, the side 20 corresponds to side 32 and side 20 + 35 corresponds to side 32 + ?.

\frac{20}{32} =\frac{20 + 35}{? + 32}

\frac{5}{8} =\frac{55}{? + 32}

\frac{1}{8}=\frac{11}{? + 32}

? + 32 = 8 * 11

? + 32 = 88

? = 56.

Hope this helps!

8 0
3 years ago
Read 2 more answers
Of the 645 students in the freshman class, 85 are left-handed. About what percentage of the students are left-handed? Round to t
jeka57 [31]

Answer:

About 13% of the freshman class are left-handed

Step-by-step explanation:

To find the percentage of a whole you need to divide the part by the whole number (85/645 = 0.1316), then you round to the nearest tenth (0.13) and change it into a percentage by moving the decimal point 2 numbers to the right. (13%)

4 0
3 years ago
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