Question

A sample of gas has a volume of 12.0 L and a pressure of 1.00 atm. If the pressure of gas

Answer 1

Answer:

The new volume of the gas will be  6  L

Explanation:

P1 = 1.0 atm

V1 = 12.0 L

P2 = 2.0 atm

Use Boyle's law here, which states that:  

$P_{1}V{1}=P_{2}V{2}$

=> $V_{2}=\frac{P_{1}V_{1} }{P_{2} }$

=> $V_{2}=\frac{1 atm*12.0L}{2atm}$

=> $V_{2}=6.0L$