Answer:
f=1/x^2-81
Step-by-step explanation:
Step 1: Multiply both sides by x^2-81.
fx3−81fx=x
Step 2: Factor out variable f.
f(x3−81x)=x
Step 3: Divide both sides by x^3-81x.
f(x3−81x)
x3−81x
=x
x3−81x
f=
1
x2−81
Answer: -20/3
Step-by-step explanation:
Given that
The cost of 1 m ribbon = Rs.75
The cost of 7/5 m ribbon
→ (7/5)×75
→ (7×75)/5
→7×15
→₹ 105
The cost of 7/5 m ribbon is ₹105.
4 tens = 40 and 5 tens = 50 … therefore the number has to be between 40 and 50
So: 40 < x <50 … this says that x is greater than 40 and less than 50
So the possible numbers would be: 41,42,43,44,45,46,47,48,49
Now the number must have 9 ones … which mean the only number would be 49
