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Anna [14]
3 years ago
9

"\frac{\sqrt[3]{60} }{\sqrt[3]{36} }" alt="\frac{\sqrt[3]{60} }{\sqrt[3]{36} }" align="absmiddle" class="latex-formula">
Please show your work.
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Step-by-step explanation:

\tt{} \frac{ \sqrt[3]{60} }{ \sqrt[3]{36} }

\tt{} \frac{ \sqrt[3]{5} }{ \sqrt[3]{3} }

\tt{} \frac{ \sqrt[3]{5} }{ \sqrt[3]{3} }  \times   \frac{ \sqrt[3]{ {3}^{2} } }{  \sqrt[3]{ {3}^{2} }  }

\tt{} \frac{ \sqrt[3]{5}  \sqrt[3]{ {3}^{2} } }{ \sqrt[3]{3} \sqrt[3]{ {3}^{2} }  }

\tt{} \frac{ \sqrt[3]{5 \times  {3}^{2} } }{ \sqrt[3]{3 \times  {3}^{2} } }

\tt{} \frac{ \sqrt[3]{5 \times 9} }{  \sqrt[3]{ {3}^{3} }  }

\tt{} \frac{ \sqrt[3]{45} }{3}

\tt{}1.18563

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Corbin is selling cheese at the farmers’ market. One wheel of cheese has a diameter of 11 inches.
sveticcg [70]

Answer:

I. 94.99 in²

II. $0.23

Step-by-step explanation:

<u>Given the following data;</u>

Diameter of wheel = 11 inches

\pi = 3.14

Cost of wheel = $21.35

Radius, r = \frac {diameter}{2}

Radius, r = \frac {11}{2} = 5.5 \; inches

<em><u>Part A</u></em>

To find the area;

We know that a wheel is circular in nature. Thus, the area of a circle is given by the formula;

Area, A = \pi r^{2}

Substituting into the equation, we have;

Area, A = 3.14 * 5.5^{2}

Area, A = 3.14*30.25

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<em><u>Part B</u></em>

To find cost per square inch;

Cost \; per \; square \; inch = \frac {Cost \; per \; wheel}{Area \; of \; wheel}

Cost \; per \; square \; inch = \frac {21.35}{94.99}

<u>Cost per square inch = $0.23</u>

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How many times larger is 9 x 10^9 than 3 x 10^-4?
andrezito [222]
The larger value is 9 x 10^9
The smaller value is 3 x 10^(-4)

Divide the larger over the smaller
Doing so will have you divide the coefficients 9 and 3 (numbers in front of the "times ten to the..." portions) to get 9/3 = 3. 
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The issue of the great compromise resolved representation.

Step-by-step explanation:

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