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Murljashka [212]
3 years ago
13

the ratio of the length to width for a rectangular yard is 3:10. if the width of the yard is 25 feet, what is the length of the

yard?
Mathematics
1 answer:
ra1l [238]3 years ago
3 0

Answer:

833.333333333333333333333333333333

Step-by-step explanation:

250*10/3 =

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Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
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Its 41 mph and 55 mph

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Factor completely<br> 6z^4 - 14z^3- 40z^2
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Answer:

Step-by-step explanation:

2z^2(3z^2 - 7z - 20)

2z^2(3z + 5)(z - 4)

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3 years ago
Hi sorry to disturb you all but can you please help me divide this problem, thank you soo much
AURORKA [14]

Answer: The Answer is 2.75

Step-by-step explanation: You first want to see how many times 56 goes into 1, which is 0, so you leave the space blank.

Then you want to drop down the 5 to get 15, and then you want to see how many times 56 can go into 15, which is 0, so you leave that space blank.

Next you want to bring down the 4 to get 154, and then see how many times 56 goes into it, which is 2 times, so you add a two in the ones place. Next you want to add two zeros after the decimal place behind the 4. You keep on bring down the numbers and seeing how many times 56 can go into them until you get your answer of 2.75.

6 0
2 years ago
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a kitten weighs four whole pounds and 2/3 of a fifth pound which mixed number represents the kittens weight?
Aneli [31]

Given that a kitten weighs four whole pounds and 2/3 of a fifth pound.

In this type of problem it is always best to break the given statement into smaller pieces then writing expression for each piece will be more easy.

"fifth" means 1/5.

so 2/3 of a fifth means product of 2/3 and 1/5 which is

\frac{2}{3}*\frac{1}{5}=\frac{2*1}{3*5}=\frac{2}{15}

Now total weight is given by

4 whole pounds and 2/3 of a fifth

= 4 + \frac{2}{15}

= 4*\frac{15}{15} + \frac{2}{15}

= \frac{60}{15} + \frac{2}{15}

= \frac{60+2}{15}

= \frac{62}{15}

Hence required fraction for the answer is \frac{62}{15}.

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3 years ago
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Find the slope of the normal line to y=x+cos(xy) at (0,1)
DaniilM [7]
Derivating the equation:

y=x+\cos(xy)\Longrightarrow y'=1+(-y\sin(xy)-xy'\sin(xy))\iff \\\\y'=1-y\sin(xy)-xy'\sin(xy)\iff y'+xy'\sin(xy)=1-y\sin(xy)\iff \\\\y'=\dfrac{1-y\sin(xy)}{1+x\sin(xy)}

So the slope of the tangent in the point (0,1) is:

y'=\dfrac{1-y\sin(xy)}{1+x\sin(xy)}\Longrightarrow y'=\dfrac{1-1\sin(0\cdot1)}{1+0\sin(0\cdot1)}\Longrightarrow y'=1

Then, the slope of the normal (n) line in the point (0,1) is:

n\cdot y'=-1\Longrightarrow n\cdot1=-1\iff\boxed{n=-1}
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3 years ago
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