In this circle we have major arc RQ which is the really big one measuring 40x, and we have minor arc RQ, which is what we are looking for. Minor arc RQ is double the measure of the angle that intercepts it. That means that minor arc RQ is 2(12x-12), which is 24x - 24. The measure of the outside of any circle will always and forever be 360 degrees; therefore, 40x + 24x - 24 = 360. Combining like terms gives us 64x = 384 and x = 6. Now sub in that 6 for the x in the angle 12x - 12 to get that that angle measures 12(6)-12 = 60. Again, the angle is half the measure of the arc it intercepts, so minor arc RQ is 120 degrees, third choice down.
Answer:
x=2
Step-by-step explanation:
When solving an algebraic equation, you have to get x alone
you do this by doing the inverse of whatever is efecting x
in this case it is x+4 so you subtract 4 from x+4
x+4-4=x
but when doing something like this, you have to do the same thing to both sides
x+4<em><u>-4</u></em>=6<u><em>-4</em></u>
x=2
please mark me brainliest!
Answer:
(0, -5), (4, -2), (-16, -17)
Step-by-step explanation:
I attach your full question in the image below
The equation is
3x-4y-8=12
Which can be rewritten as
3x-4y =12 +8
3x-20 = 4y
y = (3/4)*x - 5
We need to check each individual case
(0,-5)
y = (3/4)*(0) - 5
y = -5
True
(4,-2)
y = (3/4)*(4) - 5
y = -2
True
(8,2)
y = (3/4)*(8) - 5
y = 1
False
(-16,-17)
y = (3/4)*(-16) - 5
y = -17
True
(-1,-8)
y = (3/4)*(-1) - 5
y = -23/4
False
(-40,-34)
y = (3/4)*(-40) - 5
y = -35
False
(0,-5) (4,-2) and (-16,-17) are the solutions
Answer:
the equation of the line is y = -3x - 6
Step-by-step explanation:
Note that since (0, -6) is the y-intercept, we can write the slope-intercept equation of the line as y = mx - 6. The other given point is (-2, 0) (which happens to be the x-intercept also). Starting with y = mx - 6, replace y with 0 and x with -2:
0 = m(-2) - 6. We now solve this for the slope, m: 0 = -2m - 6 becomes
2m = -6, or m = -3.
With m = -3 and b = -6, the equation of the line is y = -3x - 6
