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vova2212 [387]
3 years ago
7

Complete this ratio table

Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer:

I think its 8,9 and 12,13

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5 1/5 - 3 4/7 =<br> A. 2 3/4<br> B. -2 3/4 <br> C. 1 16/21<br> D. -1 16/21
matrenka [14]
116/21 hope this helped !
4 0
3 years ago
An amount of $8,000 is invested at a simple interest rate of 1.5%. What is the total amount after 3 years?
aliina [53]
I=PRT
P=8000
R=0.015
T=3

I=8000*0.015*3=360

total amount=8000+360=$8360
6 0
3 years ago
Read 2 more answers
A(n)
Kryger [21]

Answer: It’s a vector

Step-by-step explanation: AP EX approved

3 0
3 years ago
Read 2 more answers
What is the vertex of a parabola defined by the equation <br> x = 5y2?
QveST [7]

Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0

3 0
3 years ago
Prove Forall x elementof Z, x^2 - 5x - 1 is odd.
Diano4ka-milaya [45]

Answer with Step-by-step explanation:

Let Z be a set of integers

We have to prove that x^2-5x-1 is odd for all value of x \inZ.

There are two cases

1.When x is an odd integer number

2.when x is even integer number

1.When x is an odd integer  number

When x is positive odd integer

Then x^2  is positive odd number (because square of odd positive number is always positive an odd number )

5x is also odd number

-5x -1 = -even number

Suppose x=3

Then -15-1=-16

Odd number - even number=Odd number

Hence ,x^2-5x-1 is an odd number .

When x is negative odd number

Then  x square is positive odd number  and 5x is negative odd term term

Therefore,odd number + odd number -1=Even  number -1=Odd number

Hence x^2-5x-1 is an odd number.

2.When  x is an even number

When x is positive even number

x square is positive even number  and 5x is positive even number

Even number -Even number -1 =Even number -odd number =Odd number

Suppose x=4

x^2-5x-1=16-20-1=-5=Odd number

When x is negative even number

Then x square is positive even number  and 5x is negative even number

x^2-5x-1=Even number +Even number -1=Even number -1=Odd number

Hence, for all elements of Zx^2-5x-1is odd.

7 0
3 years ago
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