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3 years ago

37/50 of a number is what percentage of that number?

Mathematics

2 answers:

Kazeer [188]3 years ago

4 0

Answer:

74% percentage of 37/50

Simora [160]3 years ago

4 0

Answer:

74%

Step-by-step explanation:

37/50 * 100 = 74%

When you want to obtain percentages, in most of the cases you multiply by 100.

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Please help if you can!

Assoli18 [71]

I think they would go to the rational numbers

6 0

3 years ago

For an art project, Jack used a piece of rope that was of a foot long. Daniel used a piece of rope that was 5 times as long. How

Lemur [1.5K]

5 feet

Explanation:
If jack had a 1 foot long piece of rope than we can simply multiply 1 by 5 and we get 5. Hope this helps!

8 0

3 years ago

Find x. Round to the nearest tenth: y 31° X 400 ft x = ? ]ft

Ludmilka [50]

A = 31 degree
Cos 31 degree = 400/x
X = 400/ Cos 31
= 400/0.8572
= 466.7ft

4 0

2 years ago

Can somebody tell me how to do this?

valentinak56 [21]

I'm pretty sure that 20 is 5 but other than that, I can't help with anymore.

7 0

3 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

uysha [10]

Answer:

$(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743$

$(9-8) +2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 1.926$

And we are 9% confidence that the true mean for the difference of the population means is given by:

$0.0743 \leq \mu_1 -\mu_2 \leq 1.926$

Step-by-step explanation:

For this problem we have the following data given:

$\bar X_1 = 9$ represent the sample mean for one of the departments

$\bar X_2 = 8$ represent the sample mean for the other department

$n_1 = 25$ represent the sample size for the first group

$n_2 = 20$ represent the sample size for the second group

$s_1 = 2$ represent the deviation for the first group

$s_2 =1$ represent the deviation for the second group

Confidence interval

The confidence interval for the difference in the true means is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$

The confidence given is 95% or 9.5, then the significance level is $\alpha=0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by:

$df=n_1 +n_2 -2= 20+25-2= 43$

And the critical value for this case is $t_{\alpha/2}=2.02$

And replacing we got:

$(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743$

$(9-8) +2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 1.926$

And we are 9% confidence that the true mean for the difference of the population means is given by:

$0.0743 \leq \mu_1 -\mu_2 \leq 1.926$

4 0

3 years ago

37/50 of a number is what percentage of that number? ​

37/50 of a number is what percentage of that number?